Submission #531331

#	Time	Username	Problem	Language	Result	Execution time	Memory
531331		fcw	Type Printer (IOI08_printer)	C++17	100 / 100	145 ms	51800 KiB

printer

#include <bits/stdc++.h>
#define st first
#define nd second
using lint = int64_t;
constexpr int mod = int(1e9) + 7;
constexpr int inf = 0x3f3f3f3f;
constexpr int ninf = 0xcfcfcfcf;
constexpr lint linf = 0x3f3f3f3f3f3f3f3f;
const long double pi = acosl(-1.0);
// Returns -1 if a < b, 0 if a = b and 1 if a > b.
int cmp_double(double a, double b = 0, double eps = 1e-9) {
	return a + eps > b ? b + eps > a ? 0 : 1 : -1;
}
using namespace std;

map<int, int>trie[500100];
int depth[500100];
bool flag[500100];

int main() {
	cin.tie(nullptr)->sync_with_stdio(false);
	int n;
	cin>>n;
	vector<string>a(n);
	int sz = 1;
	for(int i=0;i<n;i++){
		cin>>a[i];
		int cur = 0;
		for(char c : a[i]){
			if(!trie[cur].count(c)) trie[cur][c] = sz++;
			cur = trie[cur][c];
		}
		flag[cur] = 1;
	}
	auto get_depth = [&](auto& self, int cur, int h) -> void{
		depth[cur] = h;
		for(auto [c, v] : trie[cur]){
			self(self, v, h+1);
			depth[cur] = max(depth[cur], depth[v]);
		}
	};
	get_depth(get_depth, 0, 0);

	string ans;
	auto dfs = [&](auto& self, int cur) -> void{
		vector<pair<int, int>>v;
		if(flag[cur]) ans.push_back('P');
		for(auto [c, u] : trie[cur]){
			v.push_back({depth[u], c});
		}
		sort(v.begin(), v.end());
		for(auto [d, c] : v){
			ans.push_back(c);
			self(self, trie[cur][c]);
		}
		ans.push_back('-');
	};
	dfs(dfs, 0);
	while(ans.back() == '-') ans.pop_back();
	cout<<ans.size()<<"\n";
	for(char c : ans) cout<<c<<"\n";
	return 0;
}
/*
[  ]Leu o problema certo???
[  ]Ver se precisa de long long
[  ]Viu o limite dos fors (é n? é m?)
[  ]Tamanho do vetor, será que é 2e5 em vez de 1e5??
[  ]Testar sample
[  ]Testar casos de  borda
[  ]1LL no 1LL << i
[  ]Testar mod (é 1e9+7, mesmo?, será que o mod não ficou negativo?)
*/

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 10 / 10
• Subtask 10: 10 / 10