제출 #530867

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
530867		abc864197532	Intergalactic ship (IZhO19_xorsum)	C++17	0 / 100	2035 ms	8532 KiB

xorsum

#include <bits/stdc++.h>
using namespace std;
#define lli long long int
#define mp make_pair
#define eb emplace_back
#define pb push_back
#define pii pair<int,int>
#define X first
#define Y second
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
void abc() {cout << endl;}
template <typename T, typename ...U> void abc(T i, U ...j) {
	cout << i << ' ', abc(j...);
}
template <typename T> void printv(T l, T r) {
	for (; l != r; ++l)
		cout << *l << " \n"[l + 1 == r];
}
#ifdef Doludu
#define test(x...) abc("[" + string(#x) + "]", x);
#define owo freopen("input.txt", "r", stdin), freopen("output.txt", "w", stdout)
#else
#define test(x...) void(0)
#define owo ios::sync_with_stdio(false)
#endif
const int mod = 1e9 + 7, N = 200000;

int main () {
	owo;
	int n, q;
	cin >> n;
	vector <vector <int>> cnt(n, vector <int> (32, 0));
	for (int i = 0, x; i < n; ++i)
		cin >> x, cnt[i][x]++;
	cin >> q;
	for (int i = 0, l, r, x; i < q; ++i) {
		cin >> l >> r >> x, --l;
		assert(l + 1 == r);
		vector <int> ncnt = cnt[l];
		for (int i = 0; i < 32; ++i) {
			cnt[l][i ^ x] += ncnt[i];
			if (cnt[l][i ^ x] >= mod)
				cnt[l][i ^ x] -= mod;
		}
	}
	vector <vector <lli>> dp(n + 1, vector <lli>(3201, 0));
	vector <lli> pre(320001, 0), dp2;
	dp[0][0] = 1;
	pre[0] = 1;
	lli ans = 0;
	for (int i = 0; i < n; ++i) {
		for (int j = 0; j < 3201; ++j) {
			for (int k = 0; k < 32; ++k) if (j + k < 3201) {
				(dp[i + 1][j + k] += dp[i][j] * cnt[i][k]) %= mod;
			}
		}
		dp2.assign(320001, 0);
		for (int j = 320000; ~j; --j) {
			for (int k = 31; ~k; --k) if (j + k * (n - i) < 320001) {
				(dp2[j + k * (n - i)] += pre[j] * cnt[i][k]) %= mod;
			}
		}
		pre = dp2;
	}
	for (int i = 1; i <= n; ++i) for (int j = 0; j < 3201; ++j) {
		(ans += dp[i][j] * j * j * (n + 1)) %= mod;	
	}
	for (int j = 0; j < 320001; ++j) {
		(ans -= dp2[j] * j % mod * j) %= mod;	
	}
	if (ans < 0)
		ans += mod;
	cout << ans << '\n';
}

• Subtask 1: 0 / 4
• Subtask 2: 0 / 5
• Subtask 3: 0 / 6
• Subtask 4: 0 / 9
• Subtask 5: 0 / 8
• Subtask 6: 0 / 11
• Subtask 7: 0 / 19
• Subtask 8: 0 / 30
• Subtask 9: 0 / 8