제출 #530667

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
530667		OttoTheDino	Genetics (BOI18_genetics)	C++17	46 / 100	2089 ms	2156 KiB

genetics

#include <bits/stdc++.h>
using namespace std;

#define rep(i,s,e)                  for (int i = s; i <= e; ++i)
#define rrep(i,s,e)                 for (int i = s; i >= e; --i)
#define pb                          push_back
#define pf                          push_front
#define fi                          first
#define se                          second
#define all(a)                      a.begin(), a.end()
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);

    srand(7);

    int n, m, k; cin >> n >> m >> k;
    if (m>1800) {
        bitset<4100> x[n];

        rep (i,0,n-1) {
            string s; cin >> s;
            rep (j,0,m-1) if (s[j]=='A') x[i] |= bitset<4100>(1)<<j;
        }

        int s[n] = {};
        rep (i,0,n-1) {
            if (s[i]) continue;
            bool suc = 1;
            rep (j,0,n-1) {
                if (i==j) continue;
                int cnt = (x[i]^x[j]).count();
                if (cnt!=k) {
                    s[j] = 1;
                    suc = 0;
                }
            }
            if (suc) {
                cout << i+1 << "\n";
                break;
            }
        }
    }

    else {
        bitset<1800> x[n][4];

        unordered_map<char, int> mp;
        mp['A'] = 0;
        mp['C'] = 1;
        mp['G'] = 2;
        mp['T'] = 3;

        rep (i,0,n-1) {
            string s; cin >> s;
            rep (j,0,m-1) x[i][mp[s[j]]] |= bitset<1800>(1)<<j;
        }

        vi order(n);
        iota(all(order), 0);
        random_shuffle(all(order));

        int s[n] = {};
        rep (iii,0,n-1) {
            int i = order[iii];
            if (s[i]) continue;
            bool suc = 1;
            rep (ij,0,n-1) {
                int j = order[ij];
                if (i==j) continue;
                int cnt = 0;
                rep (l,0,3) cnt += (x[i][l]^x[j][l]).count();
                if (cnt/2!=k) {
                    s[j] = 1;
                    suc = 0;
                    break;
                }
            }
            if (suc) {
                cout << i+1 << "\n";
                break;
            }
        }
    }

    return 0;
}

• Subtask 1: 27 / 27
• Subtask 2: 19 / 19
• Subtask 3: 0 / 28
• Subtask 4: 0 / 26