이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <map>
#include "books.h"
using namespace std;
map<int, long long> m;
long long get(int x, int K) {
long long ret = 0;
for (int i = 0; i < K; i++) {
if (m.find(x + i + 1) == m.end()) m[x + i + 1] = skim(x + i + 1);
ret += m[x + i + 1];
}
return ret;
}
void solve(int N, int K, long long A, int S) {
/*int L = 0, R = N - 1;
while (L < R) {
int m = (L + R) / 2;
long long t = get(m, 1);
if (t < A) L = m + 1;
else R = m;
}
if (L + 1 >= K) {
long long t = get(L, 1) + get(0, K - 1);
if (t >= A && t <= 2 * A) {
vector<int> v;
for (int i = 0; i < K - 1; i++) v.push_back(i + 1);
v.push_back(L + 1);
answer(v);
return;
}
}*/
long long lt = 2 * A / K, rt = (A + K - 1) / K;
int l = 0, r = N - K + 1;
while (l < r) {
int m = (l + r) / 2;
long long left = get(m, 1), right = get(m + K - 1, 1);
if (left > lt) r = m;
else if (right < rt) l = m + 1;
else {
long long t = get(m, K);
if (t < A) l = m + 1;
else r = m;
}
}
long long t = get(l, K);
if (t > 2 * A || t < A) {
int l = K, r = N - 1;
while (l < r) {
int m = (l + r) / 2;
long long t = get(0, K - 1) + get(m, 1);
if (t < A) l = m + 1;
else if (t > 2 * A) r = m - 1;
else {
vector<int> v;
for (int i = 0; i < K - 1; i++) v.push_back(i + 1);
v.push_back(m + 1);
answer(v);
return;
}
}
impossible();
} else {
vector<int> v;
for (int i = 0; i < K; i++) v.push_back(l + i + 1);
answer(v);
}
}
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