제출 #528747

#제출 시각아이디문제언어결과실행 시간메모리
528747vuhoanggiapSegments (IZhO18_segments)C++17
100 / 100
2613 ms7408 KiB
#include <bits/stdc++.h> #define ii pair<int, int> #define fi first #define se second #define pb push_back #define mp make_pair #define all(x) (x).begin(), (x).end() using namespace std; const int maxN = 2e5 + 5, blockSz = 2000, maxCnt = (maxN + blockSz - 1) / blockSz; int q, t, idSeg; int l[maxN], r[maxN]; bool rem[maxN]; vector<ii> R; int n, blockCnt; int mnR[maxCnt], mxR[maxCnt]; vector<ii> Block[maxCnt]; // change sz vector<ii> BlockL[maxCnt]; vector<ii> cur; void reset() { for (auto T : cur) if (T.se) rem[T.fi] = true; R.clear(), cur.clear(); for (int i = 1; i <= idSeg; i++) if (!rem[i]) R.pb({r[i], i}); sort(all(R)); n = R.size(); blockCnt = (n + blockSz - 1) / blockSz; for (int b = 0; b <= blockCnt; b++) { Block[b].clear(); BlockL[b].clear(); } for (int b = 0; b < blockCnt; b++) { for (int i = b * blockSz; i < min(n, (b + 1) * blockSz); i++) { int id = R[i].se; Block[b].pb({r[id] - l[id] + 1, r[id]}); BlockL[b].pb({l[id], r[id]}); mxR[b] = r[id]; if (i == b * blockSz) mnR[b] = r[id]; } sort(all(Block[b])); sort(all(BlockL[b])); } } int R_lessthan(int val) { return lower_bound(all(R), mp(val, -1)) - R.begin(); } int length_lessthan(int rr, int k) { if (!blockCnt) return 0; int id = 0, ans = 0; while (id < blockCnt && mxR[id] <= rr) { ans += lower_bound(all(Block[id]), mp(k, -1)) - Block[id].begin(); id++; } for (auto T : Block[id]) if (T.se <= rr && T.fi < k) ans++; return ans; } int bruh(int ll, int rr) { if (!blockCnt) return 0; int id = blockCnt - 1; int ans = 0; while (id > 0 && mnR[id] > rr) { ans += (int)BlockL[id].size() - (upper_bound(all(BlockL[id]), mp(ll, INT_MAX)) - BlockL[id].begin()); id--; } for (auto T : BlockL[id]) if (T.fi > ll && T.se > rr) ans++; return ans; } int length_lessthan(int ll, int rr, int k) { return length_lessthan(rr, k) - length_lessthan(ll - 1, k); } bool bad(int l1, int r1, int l2, int r2) { return r1 < l2 || r2 < l1; } int query(int ll, int rr, int k) { if (rr - ll + 1 < k) return 0; int ans = n; ans -= (R_lessthan(ll + k - 1) + length_lessthan(ll + k - 1, rr, k) + bruh(rr - k + 1, rr)); if (ans < 0) { assert(false); } for (auto T : cur) if (!k || (!bad(l[T.fi], r[T.fi], ll, rr) && min(r[T.fi], rr) - max(l[T.fi], ll) + 1 >= k)) ans += (T.se ? -1 : 1); return ans; } signed main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> q >> t; for (int i = 1, lastAns = 0; i <= q; i++) { if (!(i % blockSz)) reset(); int type; cin >> type; if (type == 1) { idSeg++; cin >> l[idSeg] >> r[idSeg]; l[idSeg] ^= t * lastAns; r[idSeg] ^= t * lastAns; if (l[idSeg] > r[idSeg]) swap(l[idSeg], r[idSeg]); cur.pb({idSeg, 0}); } else if (type == 2) { int remId; cin >> remId; cur.pb({remId, 1}); } else { int ll, rr, k; cin >> ll >> rr >> k; ll ^= t * lastAns; rr ^= t * lastAns; if (ll > rr) swap(ll, rr); cout << (lastAns = query(ll, rr, k)) << '\n'; } } }
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