Submission #527161

#	Time	Username	Problem	Language	Result	Execution time	Memory
527161		zaneyu	On the Grid (FXCUP4_grid)	C++17	12 / 100	1 ms	300 KiB

grid

#include "grid.h"
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
 
//#pragma GCC optimize("unroll-loops,no-stack-protector")
//order_of_key #of elements less than x
// find_by_order kth element
using ll = long long;
using ld = long double;
using pii = pair<ll,ll>;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#define MP make_pair
const ll INF64=4e17;
const int INF=0x3f3f3f3f;
const ll MOD=1e6+7;
const ld PI=acos(-1);
const ld eps=1e-9;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<P.f<<' '<<P.s;
    return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
    REP(i,sz(V)) out<<V[i]<<((i!=sz(V)-1)?" ":"");
    return out;
}
ll mult(ll a,ll b){
    return ((a%MOD)*(b%MOD))%MOD;
}
ll mypow(ll a,ll b){
    if(b<=0) return 1;
    ll res=1LL;
    while(b){
        if(b&1) res=mult(res,a);
        a=mult(a,a);
        b>>=1;
    }
    return res;
}
const int maxn=50+5;
bool ok[maxn];
std::vector<int> SortDisks(int n) {
	vector<int> fixed;
	REP(k,n){
		REP(i,n){
			if(ok[i]) continue;
			vector<int> v;
			v.pb(i);
			REP(j,n){
				if(!ok[j] and i!=j) v.pb(j);
			}
			for(int z:fixed) v.pb(z);
			int x=PutDisks(v);
			if(x==2*n-k-1){
				//cout<<x<<' '<<i<<'\n';
				ok[i]=1;
				fixed.emplace(fixed.begin(),i);
				break;
			}
		}
	}
	vector<int> ans(n);
	REP(i,n) ans[fixed[i]]=i+1;
	return ans;
}

• Subtask 1: 12 / 12
• Subtask 2: 0 / 31
• Subtask 3: 0 / 57