제출 #525636

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
525636		Aldas25	Regions (IOI09_regions)	C++14	30 / 100	1412 ms	131076 KiB

regions

#include <bits/stdc++.h>

using namespace std;

#define FAST_IO ios_base::sync_with_stdio(0); cin.tie(0)
#define FOR(i, a, b) for(int i = (a); i <= (b); i++)
#define REP(n) FOR(O, 1, (n))
#define pb push_back
#define f first
#define s second
typedef long double ld;
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vii;
//mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const int MAXN = 250100, MAXK = 20;
const ll MOD = 1e9+7;

const ll C = 500;
const ll c = 0;

int n, r, q;
int h[MAXN];
int regSz[MAXN];
bool bgReg[MAXN];
vi adj[MAXN];

int regToId[MAXN];
int idToReg[MAXN];

int tin[MAXN], tout[MAXN];
int crT = 0;

void dfs (int v, int p = -1) {
    tin[v] = ++crT;

    for (int u : adj[v]) {
        dfs (u, v);
    }

    tout[v] = crT;
}

bool isAnc (int a, int b) {
    return (tin[a] <= tin[b] && tout[b] <= tout[a]);
}

vii nodes;
vii inReg[MAXN];
ll pref[MAXN];
ll ans[C][25100];

int main()
{
    FAST_IO;

    cin >> n >> r >> q;
    cin >> h[1];
    FOR(i, 2, n) {
        int pr; cin >> pr;
        adj[pr].pb(i);
        cin >> h[i];

    }

    FOR(i, 1, n) regSz[h[i]]++;
    int lstId = 0;
    FOR(i, 1, r) {
        bgReg[i] = (regSz[i] > c);

        if (bgReg[i]) {
            regToId[i] = ++lstId;
            idToReg[lstId] = i;
        }

       // cout << " i = " << i << " regSz = " << regSz[i] << " bg = " << bgReg[i] << endl;
       // if (bgReg[i]) cout << "     regToId[i]=" << regToId[i] << endl;
    }

    dfs(1);

    FOR(i, 1, n) {
        nodes.pb({tin[i], i});
        inReg[h[i]].pb({tin[i], i});
    }

    sort(nodes.begin(), nodes.end());
    FOR(i, 1, r) sort(inReg[i].begin(), inReg[i].end());

    FOR(i, 0, C-1) {
        if (idToReg[i] == 0) continue;
        int r = idToReg[i];

        FOR(j, 0, n) pref[j] = 0;
        for (auto p : inReg[r]) {
            int v = p.s;
            pref[tin[v]]++;
            pref[tout[v]+1]--;
        }
        FOR(j, 1, n) pref[j] += pref[j-1];

        FOR(j, 1, n) {
            int v = nodes[j-1].s;
            ans[i][h[v]] += pref[j];
        }

    }

    REP(q) {
        int r1, r2;
        cin >> r1 >> r2;

        cout << ans[regToId[r1]][r2] << endl;
    }

    return 0;
}

• Subtask 1: 15 / 15
• Subtask 2: 15 / 85