Submission #524505

#TimeUsernameProblemLanguageResultExecution timeMemory
524505DragonO_oHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++17
100 / 100
1343 ms149876 KiB
#include <bits/stdc++.h>

using namespace std;

#define x first
#define y second
#define pb push_back
#define all(a) a.begin(), a.end()
#define int long long

typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vi> vvi;
typedef vector<vll> vvll;
typedef vector<pii> vpii;
typedef vector<pll> vpll;

const int N = 1e6 + 99;

int w[N], k[N], a[N], t[N * 4], ans[N];
vi cur[N];
vpii v[N];

void build(int v, int l, int r)
{
    if (l == r) {
        t[v] = a[l];
        return;
    }
    int V = v << 1LL, mid = (l + r) >> 1LL;
    build(V, l, mid);
    build(V + 1, mid + 1, r);
    t[v] = max(t[V], t[V + 1]);
}

void upd(int v, int l, int r, int pos, int val)
{
    if (l == r) {
        t[v] = val;
        return;
    }
    int V = v << 1LL, mid = (l + r) >> 1LL;
    if (pos <= mid) {
        upd(V, l, mid, pos, val);
    }
    else {
        upd(V + 1, mid + 1, r, pos, val);
    }
    t[v] = max(t[V], t[V + 1]);
}

int get(int v, int l, int r, int L, int R)
{
    if (l == L && r == R) {
        return t[v];
    }
    int V = v << 1LL, mid = (l + r) >> 1LL;
    if (R <= mid) {
        return get(V, l, mid, L, R);
    }
    if (L > mid) {
        return get(V + 1, mid + 1, r, L, R);
    }
    return max(get(V, l, mid, L, mid), get(V + 1, mid + 1, r, mid + 1, R));
}

signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int n, m;
    cin >> n >> m;
    for (int i = 1; i <= n; ++i) {
        cin >> w[i];
    }
    vpii st;
    st.pb({ w[1], 1 });
    a[1] = -1;
    for (int i = 2; i <= n; ++i) {
        while (!st.empty() && st.back().x <= w[i]) {
            st.pop_back();
        }
        if (!st.size()) {
            a[i] = -1;
        }
        else {
            a[i] = st.back().x + w[i];
            cur[st.back().y].pb(i);
        }
        st.pb({ w[i], i });
    }
    build(1, 1, n);
    for (int i = 1; i <= m; ++i) {
        int l, r;
        cin >> l >> r >> k[i];
        v[l].pb({ r, i });
    }
    for (int l = 1; l <= n; ++l) {
        for (auto[r, i] : v[l]) {
            if (get(1, 1, n, l, r) <= k[i]) {
                ans[i] = 1;
            }
        }
        for (int pos : cur[l]) {
            upd(1, 1, n, pos, -1);
        }
    }
    for (int i = 1; i <= m; ++i) {
        cout << ans[i] << "\n";
    }
}
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