Submission #523679

#	Time	Username	Problem	Language	Result	Execution time	Memory
523679		maks007	Maxcomp (info1cup18_maxcomp)	C++14	15 / 100	340 ms	272 KiB

maxcomp

#include <bits/stdc++.h>
 
using namespace std;
 
int dis(pair <int,int>a, pair <int,int> b) {
	return abs(a.first - b.first) + abs(a.second - b.second);
}
 
int main(void) {
	int n, m;
	cin >> n >> m;
	if(n == 1) {
		vector <int> a(m);
		for(int i = 0; i < m; i ++) cin >> a[i];
		int ans = INT_MIN;
		for(int i = 0; i < m; i ++) {
			for(int end = i; end < m; end ++) {
				ans = max(ans, *max_element(a.begin() + i, a.begin() + end) - *min_element(a.begin() + i, a.begin() + end) - (end - i));
			//	cout << *max_element(a.begin() + i, a.begin() + end) << " " << *min_element(a.begin() + i, a.begin() + end) << endl;
			}
		}
		cout << ans;
		return false;
	}
	vector <vector <int> > g(n+2, vector <int> (m+2, -1));
	vector <vector <int> > used(n+2, vector <int> (m+2, 0));
	vector <vector <int> > dis(n+2, vector <int> (m+2, 0));
	queue <pair <int,int>> q;
	int it[] = {0, 0, +1, -1};
	int jt[] = {+1, -1, 0, 0};
	function <int(int, int, pair <int,int>, pair <int,int>)> can=[&](int mn, int mx, pair <int,int> s, pair <int,int> e) {
		for(int i = 1; i <= n; i ++) {
			for(int j = 1; j <= m; j ++) used[i][j] = dis[i][j] = 0;
		}
		q.push(s);
		used[s.first][s.second] = 1;
		dis[s.first][s.second] = 1;
		
		while(!q.empty()) {
			pair <int,int> v = q.front();
			q.pop();
			for(int to = 0; to < 4; to ++) {
				int ni = v.first + it[to];
				int nj = v.second + jt[to];
				if(!used[ni][nj] and g[ni][nj] != -1 and g[ni][nj] >= mn and g[ni][nj] <= mx) {
					q.push({ni, nj});
					used[ni][nj] = 1;
					dis[ni][nj] = dis[v.first][v.second] + 1;
				}
			}
		}
		return dis[e.first][e.second];
	};
	pair <int,int> start;
	int mx = 0;
	for(int i = 1; i <= n; i ++) {
		for(int j = 1; j <= m; j ++){
			cin >> g[i][j];
			if(g[i][j] > mx) {
				mx = g[i][j];
				start = {i, j};
			}
		}
	}
	int ans = 0;
 
	for(int i = 1; i <= n; i ++) {
		for(int j = 1; j <= m; j ++) {
			if(can(g[i][j], mx, start, {i, j})) {
				
				ans = max(mx - g[i][j] - can(g[i][j], mx, start, {i, j}), ans);
			}
		}
	}
	cout << ans;
	return false;
}

• Subtask 1: 0 / 15
• Subtask 2: 15 / 15
• Subtask 3: 0 / 30
• Subtask 4: 0 / 40