Submission #523647

#	Time	Username	Problem	Language	Result	Execution time	Memory
523647		maks007	Maxcomp (info1cup18_maxcomp)	C++14	15 / 100	345 ms	280 KiB

maxcomp

#include <bits/stdc++.h>
 
using namespace std;

int dis(pair <int,int>a, pair <int,int> b) {
	return abs(a.first - b.first) + abs(a.second - b.second);
}

int main(void) {
	int n, m;
	cin >> n >> m;
	if(n == 1) {
		vector <int> a(m);
		for(int i = 0; i < m; i ++) cin >> a[i];
		int ans = INT_MIN;
		for(int i = 0; i < m; i ++) {
			for(int end = i; end < m; end ++) {
				ans = max(ans, *max_element(a.begin() + i, a.begin() + end) - *min_element(a.begin() + i, a.begin() + end) - (end - i));
			//	cout << *max_element(a.begin() + i, a.begin() + end) << " " << *min_element(a.begin() + i, a.begin() + end) << endl;
			}
		}
		cout << ans;
		return false;
	}
	vector <vector <int> > g(n+2, vector <int> (m+2, -1));
	vector <vector <int> > used(n+2, vector <int> (m+2, 0));
	queue <pair <int,int>> q;
	int it[] = {0, 0, +1, -1};
	int jt[] = {+1, -1, 0, 0};
	function <int(int, int, pair <int,int>, pair <int,int>)> can=[&](int mn, int mx, pair <int,int> s, pair <int,int> e) {
		for(int i = 1; i <= n; i ++) {
			for(int j = 1; j <= m; j ++) used[i][j] = 0;
		}
		q.push(s);
		used[s.first][s.second] = 1;
		while(!q.empty()) {
			pair <int,int> v = q.front();
			q.pop();
			for(int to = 0; to < 4; to ++) {
				int ni = v.first + it[to];
				int nj = v.second + jt[to];
				if(!used[ni][nj] and g[ni][nj] != -1 and g[ni][nj] >= mn and g[ni][nj] <= mx) {
					q.push({ni, nj});
					used[ni][nj] = 1;
				}
			}
		}
		return used[e.first][e.second];
	};
	for(int i = 1; i <= n; i ++) {
		for(int j = 1; j <= m; j ++) cin >> g[i][j];
	}
	int ans = INT_MAX;

	for(int i = 1; i <= n; i ++) {
		for(int j = 1; j <= m; j ++) {
			for(int k = 1; k <= n; k ++) {
				for(int l = 1; l <= m; l ++) {
					if(can(min(g[i][j], g[k][l]), max(g[i][j], g[k][l]), {i, j}, {k, l}) == 1) {
						if(max(g[i][j], g[k][l])
							- min(g[i][j], g[k][l]) - (abs(i - k) + abs(j - l)+1) < 0) continue;
						ans = min(ans, max(g[i][j], g[k][l])
							- min(g[i][j], g[k][l]) - (abs(i - k) + abs(j - l)+1));
					}
				}
			}
		}
	}
	cout << ans;
	return false;
}

• Subtask 1: 0 / 15
• Subtask 2: 15 / 15
• Subtask 3: 0 / 30
• Subtask 4: 0 / 40