Submission #523319

# Submission time Handle Problem Language Result Execution time Memory
523319 2022-02-07T12:52:44 Z sidon Snake Escaping (JOI18_snake_escaping) C++17
Compilation error
0 ms 0 KB
#include <bits/stdc++.h>
using namespace std;

const int B = 13, N = 1<<20, SZ = pow(3, B);

int Q, dp[SZ], ans[N], id[N];
string A, inp;
__int8 x[N], y[N];

int main() {
	ios::sync_with_stdio(0), cin.tie(0);
	cin >> Q >> Q >> A;
	A.resize(N, '0');

	for(int i = 0; i < Q; ++i) {
		cin >> inp;
		reverse(begin(inp), end(inp));
		inp.resize(20, '0');

		for(int k = 0, p = 1; k < B; ++k, p *= 3)
			id[i] += p * ((48 < inp[k]) + (62 < inp[k]));

		for(int k = 0; k < 20-B; ++k) {
			if(inp[k+B] != '?')	y[i] |= 1<<k;
			if(inp[k+B] == '1')	x[i] |= 1<<k;
		}
	}

	for(int s = 0; s < (1<<(20-B)); ++s) {
		memset(dp, 0, sizeof dp);

		for(int i = 0; i < (1<<B); ++i) {
			int j = 0;
			for(int k = 0, p = 1; k < B; ++k, p *= 3)
				if(i & (1<<k)) j += p;

			dp[j] += A[i | (s << B)] - '0';
		}

		for(int i = 1; i < SZ; ++i) {
			int j = -1, pw = 1;

			for(int k = 0, p = i; k < B; ++k, p /= 3, pw *= 3)
				if((p % 3) > 1) j = k, k = B;
			
			if(j >= 0)
				pw /= 3, dp[i] = dp[i - pw] + dp[i - 2 * pw];
		}

		for(int i = 0; i < Q; ++i)
			if(!((x[i] ^ s) & y[i]))
				ans[i] += dp[id[i]];
	}

	for(int i = 0; i < Q; ++i)
		cout << ans[i] << '\n';
}

Compilation message

snake_escaping.cpp:8:1: error: '__int8' does not name a type; did you mean 'u_int'?
    8 | __int8 x[N], y[N];
      | ^~~~~~
      | u_int
snake_escaping.cpp: In function 'int main()':
snake_escaping.cpp:24:24: error: 'y' was not declared in this scope
   24 |    if(inp[k+B] != '?') y[i] |= 1<<k;
      |                        ^
snake_escaping.cpp:25:24: error: 'x' was not declared in this scope
   25 |    if(inp[k+B] == '1') x[i] |= 1<<k;
      |                        ^
snake_escaping.cpp:51:10: error: 'x' was not declared in this scope
   51 |    if(!((x[i] ^ s) & y[i]))
      |          ^
snake_escaping.cpp:51:22: error: 'y' was not declared in this scope
   51 |    if(!((x[i] ^ s) & y[i]))
      |                      ^