#include <iostream>
#include <fstream>
#include <vector>
#include <algorithm>
#define YMAX 1e9
#define NMAX 200000 //doua sute cincizeci de mii
using namespace std;
ifstream fin ("test.in");
ofstream fout ("test.out");
int R, C, N, T;
pair <int, int> s[NMAX + 1];
int t[25][NMAX + 1];
int lg[NMAX + 1];
int cautareBinara(int x, int y){
/*
Imi returneaza, din lista de trambuline verzi, numarul celei de pe linia x, cu lowerboundul ei = y
daca nu exista niciunul pe linia x, returneaza 0
*/
int lo = 0;
int hi = N + 1;
int ans = 0;
while(hi - lo > 1){
int mid = lo + (hi - lo) / 2;
if(s[mid].first > x){
hi = mid;
}
else if(s[mid].first < x){
lo = mid;
}
else if(s[mid].second < y){
lo = mid;
}
else {
ans = mid;
hi = mid;
}
}
return ans;
}
int stramos(int node, int nr){
if(nr == 0){
return s[node].second;
}
for(int i = lg[nr]; i >= 0; i--){
if( (1 << i) <= nr ){
node = t[i][node];
nr -= (1 << i);
}
}
///daca node ajunge sa fie 0, inseamna ca nu exista al nr-lea stramos al lui node
///dar la mine trebuie sa existe ca sa zic 'Yes', ca altfel inseamna ca nu am destule trambuline pe drum
///adica inseamna ca nu am trambuline de la (xs, xf) destule
///si atunci vreau sa returnez ceva care sa ma faca sa afisez 'No', adica returnez un 'y' f mare, pentru ca eu urmeaza sa il compar cu yf
if(node == 0){
return YMAX + 1;
}
return s[node].second; ///returneaza 'y'-ul celui de-al 'nr'-ulea stramos al lui 'node'
}
void computeLg(){
lg[1] = 0;
for(int i = 2; i <= N; i++){
lg[i] = lg[i / 2] + 1;
}
}
int main()
{
ios_base::sync_with_stdio(NULL);
cin.tie(0);
cout.tie(0);
computeLg();
cin >> R >> C >> N; ///globale
for(int i = 1; i <= N; i++){
cin >> s[i].first >> s[i].second;
}
sort(s + 1, s + N + 1);
for(int i = 1; i <= N; i++){
int aux = cautareBinara(s[i].first + 1, s[i].second);
t[0][i] = aux;
}
for(int i = 1; i <= 19; i++){
for(int j = 1; j <= N; j++){
t[i][j] = t[i - 1][ t[i - 1][j] ];
}
}
cin >> T; ///global
for(int Q = 1; Q <= T; Q++){
int xs, ys, xf, yf;
cin >> xs >> ys >> xf >> yf;
if(xf == xs){ ///caz special ca altfel am niste valori cu -1 si nu are sens
if(ys <= yf){
cout << "Yes\n";
}
else {
cout << "No\n";
}
}
else if(xs > xf || ys > yf){
cout << "No\n";
}
else {
int st = cautareBinara(xs, ys); ///caut cel mai din stanga valid de pe linia 'xs'
if(st == 0){
cout << "No\n";
}
else if( stramos(st, xf - 1 - xs) <= yf ){ ///verific al 'xf - 1 - xs'-lea stramos al acestuia si verific daca e mai mic ca 'yf'
cout << "Yes\n";
}
else {
cout << "No\n";
}
}
}
return 0;
}
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
3 ms |
1100 KB |
expected NO, found YES [2nd token] |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
64 ms |
17476 KB |
expected NO, found YES [1st token] |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
172 ms |
18240 KB |
200000 token(s): yes count is 110486, no count is 89514 |
2 |
Correct |
171 ms |
18256 KB |
200000 token(s): yes count is 114664, no count is 85336 |
3 |
Correct |
180 ms |
18116 KB |
200000 token(s): yes count is 86232, no count is 113768 |
4 |
Correct |
182 ms |
18272 KB |
200000 token(s): yes count is 94603, no count is 105397 |
5 |
Correct |
173 ms |
18176 KB |
200000 token(s): yes count is 94148, no count is 105852 |
6 |
Correct |
179 ms |
18156 KB |
200000 token(s): yes count is 97163, no count is 102837 |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
7 ms |
972 KB |
expected NO, found YES [59th token] |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Incorrect |
185 ms |
18396 KB |
expected NO, found YES [23rd token] |
2 |
Halted |
0 ms |
0 KB |
- |