This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define FAST_IO ios_base::sync_with_stdio(0); cin.tie(nullptr)
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define REP(n) FOR(O, 1, (n))
#define f first
#define s second
#define pb push_back
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<pii> vii;
typedef vector<ll> vl;
const int MAXN = 50100;
int par[MAXN], sz[MAXN];
int find (int a) {return par[a] = par[a]==a ? a : find(par[a]);}
bool same (int a, int b) {return find(a) == find(b);}
void unite (int a, int b) {
a = find(a);
b = find(b);
if (a==b) return;
par[b] = a;
sz[a] += sz[b];
}
int n, m, q;
void dsuReset () {
FOR(i, 0, n) {
par[i] = i;
sz[i] = 1;
}
}
int ui[MAXN], vei[MAXN], di[MAXN];
int ti[MAXN], ai[MAXN], bi[MAXN];
vector<pair<int, pii>> edges;
int ans[MAXN];
vector<pair<pii, int>> queries;
void solve4 () {
dsuReset();
FOR(i, 1, m) {
edges.pb({di[i], {ui[i], vei[i]}});
}
sort(edges.begin(), edges.end());
reverse(edges.begin(), edges.end());
FOR(i, 1, q) {
if (ti[i] == 2) {
queries.pb({{bi[i], ai[i]}, i});
}
}
sort(queries.begin(), queries.end());
reverse(queries.begin(), queries.end());
int qId = 0, eId = 0;
while (qId < (int)queries.size()) {
if (eId < m && edges[eId].f >= queries[qId].f.f) {
int u = edges[eId].s.f;
int v = edges[eId].s.s;
unite(u,v);
eId++;
} else {
int v = queries[qId].f.s;
int id = queries[qId].s;
ans[id] = sz[find(v)];
qId++;
}
}
FOR(i, 1, q) if (ti[i] == 2) cout << ans[i] << "\n";
}
void solve1 () {
FOR(i, 1, q) {
if (ti[i] == 1) {
int id = ai[i];
int newW = bi[i];
di[id] = newW;
} else {
dsuReset();
int v = ai[i];
int w = bi[i];
FOR(j, 1, m) {
if (di[j] >= w)
unite (ui[j], vei[j]);
}
cout << sz[find(v)] << "\n";
}
}
}
int main()
{
FAST_IO;
cin >> n >> m;
FOR(i, 1, m)
cin >> ui[i] >> vei[i] >> di[i];
cin >> q;
FOR(i, 1, q) {
cin >> ti[i] >> ai[i] >> bi[i];
}
bool sub4 = true;
FOR(i, 1, q) if (ti[i] != 2) sub4 = false;
if (sub4)
solve4();
else
solve1();
return 0;
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |