이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<iostream>
#include<algorithm>
#include<string>
#include<vector>
#include<unordered_set>
#define all(x) x.begin(), x.end()
using namespace std;
typedef long long ll;
const int N = 1e5 + 9, mod = 998244353;
int n;
int a[11][62][62][2];
bool palind(string s) {
int l(0), r(s.size() - 1);
while (l < r) {
if (s[l] != s[r]) return false;
++l, --r;
}
return true;
}
int num(char c) {
if ('a' <= c && c <= 'z') return c - 'a';
if ('A' <= c && c <= 'Z') return c - 'A' + 26;
if ('0' <= c && c <= '9') return c - '0' + 52;
return -1;
}
ll calc(int len, int i, int j) {
if (i != j) {
if (i > j) swap(i, j);
return a[len][i][j][0];
}
return (a[len][i][j][1] + a[len][i][j][0] * 2) % mod;
}
ll perm[62][62][62][62], d[62][62][62];
void build_d(int len) {
for (int i1 = 0; i1 < n; ++i1)
for (int i2 = i1; i2 < n; ++i2)
for (int i3 = i2; i3 < n; ++i3) {
d[i1][i2][i3] = 0;
for (int i = 0; i < n; ++i)
(d[i1][i2][i3] += calc(len, i, i1) * calc(len, i, i2) % mod * calc(len, i, i3)) %= mod;
}
}
int main() {
cin.tie(NULL)->sync_with_stdio(false);
cin >> n;
unordered_set<string> S;
vector<int> ch;
for (int ii = 0; ii < n; ++ii) {
string s; cin >> s;
if (S.count(s)) continue;
int i = num(s[0]), j = num(s.back());
if (i > j) swap(i, j);
ch.push_back(i);
ch.push_back(j);
++a[s.size()][i][j][palind(s)];
reverse(all(s));
S.insert(s);
}
sort(all(ch));
ch.resize(unique(all(ch)) - ch.begin());
n = ch.size();
for (int len = 3; len <= 10; ++len)
for (int i = 0; i < n; ++i)
for (int j = i; j < n; ++j) {
int i1 = ch[i], i2 = ch[j];
a[len][i][j][0] = a[len][i1][i2][0];
a[len][i][j][1] = a[len][i1][i2][1];
}
for (int i1 = 0; i1 < n; ++i1)
for (int i2 = i1; i2 < n; ++i2)
for (int i3 = i2; i3 < n; ++i3)
for (int i4 = i3; i4 < n; ++i4) {
perm[i1][i2][i3][i4] = i1 == i4 ? 1 : i1 == i3 || i2 == i4 ? 4 : i1 == i2 && i3 == i4 ? 6 : i1 == i2 || i2 == i3 || i3 == i4 ? 12 : 24;
}
ll ans(0);
for (int len = 3; len <= 10; ++len) {
build_d(len);
for (int i1 = 0; i1 < n; ++i1)
for (int i2 = i1; i2 < n; ++i2)
for (int i3 = i2; i3 < n; ++i3)
for (int i4 = i3; i4 < n; ++i4)
(ans += d[i1][i2][i3] * d[i1][i2][i4] % mod * d[i1][i3][i4] % mod * d[i2][i3][i4] % mod * perm[i1][i2][i3][i4]) %= mod;
}
cout << ans << '\n';
}
/** /\_/\
* (= ._.)
* / >0 \>1
**/
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |