제출 #518634

#제출 시각아이디문제언어결과실행 시간메모리
518634K4YANNecklace (Subtask 1-3) (BOI19_necklace1)C++17
9 / 85
1593 ms384 KiB
//Be Name Khoda #include<bits/stdc++.h> #pragma GCC optmize("Ofast,unroll-loops") #pragma GCC target ("avx2,tune=native") using namespace std; #define ll long long #define ld long double #define all(x) x.begin(), x.end() #define pii pair<int, int> #define pll pair<ll, ll> #define plll pair<pll, ll> const int mxn = 3e3 + 16; const ll md = 1e9 + 7, md2 = 998244353, p1 = 27, p2 = 31; ll n, m, q, w, t, sum; int mid, l, r; int g[mxn], g2[mxn], f[mxn], f2[mxn], taq[mxn], qat[mxn]; string s, h; void input() { cin >> s >> h; } inline ll tav(ll a, ll b, ll d) { ll res = 1; while(b > 0) { if(b & 1) res *= a; res %= d; a *= a; a %= d; b >>= 1; } return res; } inline void GGL() { taq[0] = qat[0] = 1; taq[1] = tav(p1, md - 2, md); qat[1] = tav(p2, md2 - 2, md2); for(int i = 2; i < mxn; i++) { taq[i] = 1LL * taq[i - 1] * taq[1] % md; qat[i] = 1LL * qat[i - 1] * qat[1] % md2; } return; } inline void build_hash() { n = int(s.size()); q = 0, w = 1; for(int i = 0; i < n; i++) { q = q + (1LL * w * (s[i] - 'a')); q %= md; g[i] = q; w *= p1; w %= md; } q = 0, w = 1; for(int i = 0; i < n; i++) { q = q + (1LL * w * (s[i] - 'a')); q %= md2; g2[i] = q; w *= p2; w %= md2; } return; } inline void build_hash2() { m = int(h.size()); q = 0, w = 1; for(int i = 0; i < m; i++) { q = q + (1LL * w * (h[i] - 'a')); q %= md; f[i] = q; w *= p1; w %= md; } q = 0, w = 1; for(int i = 0; i < m; i++) { q = q + (1LL * w * (h[i] - 'a')); q %= md2; f2[i] = q; w *= p2; w %= md2; } return; } inline pii hashG(int lx, int rx) { if(lx == 0) { q = g[rx - 1], w = g2[rx - 1]; return make_pair(q, w); } q = g[rx - 1] - g[lx - 1]; q %= md; q += md; q %= md; q = 1LL * q * taq[lx] % md; w = g2[rx - 1] - g2[lx - 1]; w %= md2; w += md2; w %= md2; w = 1LL * w * qat[lx] % md2; return make_pair(q, w); } inline pii hashF(int lx, int rx) { if(lx == 0) { q = f[rx - 1], w = f2[rx - 1]; return make_pair(q, w); } q = f[rx - 1] - f[lx - 1]; q %= md; q += md; q %= md; q = 1LL * q * taq[lx] % md; w = f2[rx - 1] - f2[lx - 1]; w %= md2; w += md2; w %= md2; w = 1LL * w * qat[lx] % md2; return make_pair(q, w); } inline int bs(int a, int b) { l = 0, r = min(n - a, m - b); for(int i = 11; i > -1; i--) { if(l + (1 << i) > r) continue; if(hashG(a, a + l + (1 << i)) == hashF(b, b + l + (1 << i))) l += (1 << i); } return l; } inline int bs2(int a, int b) { l = 0, r = min(1LL * a, m - b - sum); for(int i = 11; i > -1; i--) { if(l + (1 << i) > r) continue; if(hashG(a - (l + (1 << i)), a) == hashF(b + sum, b + sum + l + (1 << i))) l += (1 << i); } return l; } void solve() { GGL(); build_hash(); build_hash2(); int ans = 0, st1 = -1, st2 = -1; for(int i = 0; i < n; i++) { for(int j = 0; j < m; j++) { if(m - j < ans) break; if(s[i] != h[j]) continue; sum = bs(i, j); w = bs2(i, j); sum += w; if(sum > ans) { st1 = i - w; st2 = j; ans = sum; } } } reverse(all(h)); build_hash2(); for(int i = 0; i < n; i++) { for(int j = 0; j < m; j++) { if(m - j < ans) break; if(s[i] != h[j]) continue; sum = bs(i, j); w = bs2(i, j); sum += w; if(sum > ans) { st1 = i - w; st2 = m - j - sum; ans = sum; } } } cout << ans << "\n"; cout << st1 << " " << st2 << "\n"; return; } int main() { ios::sync_with_stdio(false); cin.tie(NULL); input(), solve(); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

necklace.cpp:4: warning: ignoring '#pragma GCC optmize' [-Wunknown-pragmas]
    4 | #pragma GCC optmize("Ofast,unroll-loops")
      | 
necklace.cpp: In function 'long long int tav(long long int, long long int, long long int)':
necklace.cpp:32:9: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
   32 |         if(b & 1) res *= a; res %= d;
      |         ^~
necklace.cpp:32:29: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
   32 |         if(b & 1) res *= a; res %= d;
      |                             ^~~
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