이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int kN = 1e5;
const int64_t INF = 2e18L;
int n;
vector<pair<int, int>> g[1 + kN];
int64_t ans, du[1 + kN], dv[1 + kN];
void minSelf(int64_t &x, int64_t y) {
if (y < x) {
x = y;
}
}
void Dijkstra(int s, int64_t d[]) {
for (int v = 1; v <= n; ++v) {
d[v] = INF;
}
priority_queue<pair<int64_t, int>, vector<pair<int64_t, int>>, greater<pair<int64_t, int>>> pq;
d[s] = 0;
pq.emplace(0, s);
while (!pq.empty()) {
int64_t cost;
int u;
tie(cost, u) = pq.top();
pq.pop();
if (cost != d[u]) {
continue;
}
for (auto it : g[u]) {
int v, w;
tie(v, w) = it;
if (d[v] > d[u] + w) {
d[v] = d[u] + w;
pq.emplace(d[v], v);
}
}
}
}
void solve(int s, int t) {
/// drumul optim de la u la v poate sa intersecteze un drum continut intr-un drum de cost minim de la s la t
/// dp[node][0 / 1] =def= u si v se deplaseaza pana la cate un nod de pe un ACELASI drum de cost
/// minim de la s la node astfel incat dp[node][0] + dp[node][1] este minim(ma intereseaza doar cat
/// au de facut pana la nodurile respective pentru ca intre ele folosesc commuter-ul si va fi gratis)
/// in timp ce fac drumul minim de la s la t actualizez dinamica
vector<int64_t> d(n + 1, INF);
vector<vector<int64_t>> dp(n + 1, vector<int64_t>(2, INF));
dp[s][0] = du[s];
dp[s][1] = dv[s];
priority_queue<pair<int64_t, int>, vector<pair<int64_t, int>>, greater<pair<int64_t, int>>> pq;
d[s] = 0;
pq.emplace(0, s);
while (!pq.empty()) {
int64_t cost;
int from;
tie(cost, from) = pq.top();
pq.pop();
if (cost != d[from]) {
continue;
}
for (auto it : g[from]) {
int to, w;
tie(to, w) = it;
if (d[to] > d[from] + w) {
dp[to][0] = min(dp[from][0], du[to]);
dp[to][1] = min(dp[from][1], dv[to]);
d[to] = d[from] + w;
pq.emplace(d[to], to);
} else if (d[to] == d[from] + w) {
if (dp[to][0] + dp[to][1] > min(dp[from][0], du[to]) + min(dp[from][1], dv[to])) {
dp[to][0] = min(dp[from][0], du[to]);
dp[to][1] = min(dp[from][1], dv[to]);
}
}
}
}
minSelf(ans, dp[t][0] + dp[t][1]);
}
void testCase() {
int m, s, t, u, v;
cin >> n >> m >> s >> t >> u >> v;
for (int i = 0; i < m; ++i) {
int u, v, w;
cin >> u >> v >> w;
g[u].emplace_back(v, w);
g[v].emplace_back(u, w);
}
Dijkstra(u, du);
Dijkstra(v, dv);
ans = du[v]; /// poate drumul optim de la u la v este cel direct dintre ele fara commuter pass
solve(s, t); /// u - x - y - v
cout << ans << '\n';
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int tests = 1;
for (int tc = 0; tc < tests; ++tc) {
testCase();
}
return 0;
}
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