Submission #5149

#TimeUsernameProblemLanguageResultExecution timeMemory
5149tncks0121K blocks (IZhO14_blocks)C++98
53 / 100
1000 ms83512 KiB
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <stdlib.h> #include <string.h> #include <memory.h> #include <math.h> #include <assert.h> #include <stack> #include <queue> #include <map> #include <set> #include <algorithm> #include <string> #include <functional> #include <vector> #include <deque> #include <utility> #include <bitset> #include <limits.h> #include <time.h> using namespace std; typedef long long ll; typedef unsigned long long llu; typedef double lf; typedef unsigned int uint; typedef long double llf; typedef pair<int, int> pii; const int N_ = 100005, K_ = 105; int N, K; int A[N_]; ll Table[N_][K_]; int main() { scanf("%d%d", &N, &K); for(int i = 1; i <= N; i++) scanf("%d", A+i); for(int k = 0; k <= K; k++) Table[1][k] = (ll)1e15; Table[1][1] = A[1]; for(int i = 2; i <= N; i++) { for(int k = 0; k <= K; k++) Table[i][k] = (ll)1e15; for(int k = 1; k <= i && k <= K; k++) { ll mx = 0; for(int j = i; j > 0; j--) { mx = max(mx, (ll)A[j]); if(k <= j) Table[i][k] = min(Table[i][k], Table[j - 1][k - 1] + mx); } } } printf("%lld\n", Table[N][K]); return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...