이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "minerals.h"
#include<bits/stdc++.h>
#define all(x) begin(x), end(x)
using namespace std;
bitset<90000> on;
int uwusgi(int x) {
on.flip(x);
return Query(x);
}
#define Query uwusgi
void Solve(int N) {
vector<int> A, B, C(N), V;
{
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
vector<int> ord(2*N);
iota(all(ord), 1);
shuffle(all(ord), rng);
int lst = 0;
for(auto i : ord) {
int cc = Query(i);
if(cc == lst) {
V.push_back(A.size());
}
(cc==lst ? B : A).push_back(i);
lst = cc;
}
}
// int CC = 0;
for(int b = 0; b < 16; b++) {
int lst = 0;
for(int i = 0; i < N; i++)
if(((i>>b)&1)^on[A[i]])
lst = Query(A[i]);
vector<int> cnt(1<<16), cnto(1<<16);
for(auto i : C) cnt[i]++;
for(int i = 0; i < 1<<b; i++) {
for(int j = 0; j < 1<<(16-b); j++) {
int c = i | (j<<b);
if(c<N)
cnto[i] += j&1;
}
}
for(int i = 0; i < N; i++) {
if((C[i]|(1<<b)) > V[i] || !cnto[C[i]]) {cnt[C[i]]--;continue;}
if(cnto[C[i]]) {
int qq = -1;
if(cnto[C[i]] == cnt[C[i]] && lst != qq) qq = lst;//cout << "HEY"<<endl;
else qq = Query(B[i]);
if(lst == qq) cnto[C[i]]--;
C[i] |= (lst == qq)<<b;
lst = qq;
} else {
C[i] |= cnto[C[i]]<<b;
cnto[C[i]]--;
}
cnt[C[i]]--;
}
// for(auto i : C) cout << i << " "; cout << endl;
}
for(int i = 0; i < N; i++)
Answer(A[C[i]], B[i]);
}
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