제출 #514598

#제출 시각아이디문제언어결과실행 시간메모리
514598fatemetmhrTwo Antennas (JOI19_antennas)C++17
100 / 100
908 ms61276 KiB
// ~Be name khoda~ // #include<bits/stdc++.h> using namespace std; typedef long long ll; #define pb push_back #define mp make_pair #define all(x) x.begin(), x.end() #define fi first #define se second #define cl clear #define endll '\n' const int maxn = 1e6 + 10; const int maxn5 = 2e5 + 10; const int maxnt = 8e5 + 10; const int maxn3 = 1e3 + 10; const int mod = 1e9 + 7; const ll inf = 1e18; struct javab{ ll val1, val2, mn, mx, ans1, ans2; javab(){ val1 = val2 = mn = mx = ans1 = ans2 = -1 * inf; return; } } seg[maxnt]; int a[maxn5], b[maxn5], h[maxn5], l[maxn5], r[maxn5]; vector <pair<int, pair<int, int>>> eve; vector <int> req; ll out[maxn5]; void shift(int, int, int); inline bool cmp(int i, int j){return l[i] > l[j];} inline void recalc(int v){ seg[v].ans1 = max(seg[v].ans1, seg[v].val1 + seg[v].mn); seg[v].ans2 = max(seg[v].ans2, seg[v].val2 + seg[v].mx); return; } inline javab multi(javab a, javab b, javab c, bool ty){ javab ret; ret.val1 = max(b.val1, c.val1); ret.val2 = max(b.val2, c.val2); ret.ans1 = max(b.ans1, c.ans1); ret.ans2 = max(b.ans2, c.ans2); if(ty){ ret.ans1 = max(ret.ans1, a.ans1); ret.ans2 = max(ret.ans2, a.ans2); } return ret; } inline void setval(int l, int r, int ind, ll va1, ll va2, int v){ if(r - l == 1){ seg[v].mn = seg[v].mx = -1 * inf; seg[v].val1 = va1; seg[v].val2 = va2; //recalc(v); //cout << "ok setval " << l << ' ' << r << ' ' << seg[v].val1 << ' ' << seg[v].ans1 << endl; return; } int mid = (l + r) >> 1; shift(v, l, r); if(ind < mid) setval(l, mid, ind, va1, va2, v * 2); else setval(mid, r, ind, va1, va2, v * 2 + 1); seg[v] = multi(seg[v], seg[v * 2], seg[v * 2 + 1], true); //cout << "righttt " << l << ' ' << r << ' ' << seg[v].ans1 << ' ' << seg[v].mn << endl; return; } inline void setmax(int l, int r, int lq, int rq, ll va1, ll va2, int v){ //cout << "em vel " << l << ' ' << r << ' ' << lq << ' ' << rq << endl; if(rq <= l || r <= lq) return; if(lq <= l && r <= rq){ seg[v].mn = max(seg[v].mn, va1); seg[v].mx = max(seg[v].mx, va2); recalc(v); // << ' ' << l << ' ' << r << ' ' << va1 << ' ' << seg[v].ans1 << ' ' << seg[v].mn << ' ' << seg[v].val1 << endl; return; } int mid = (l + r) >> 1; shift(v, l, r); setmax(l, mid, lq, rq, va1, va2, v * 2); setmax(mid, r, lq, rq, va1, va2, v * 2 + 1); seg[v] = multi(seg[v], seg[v * 2], seg[v * 2 + 1], true); return; } inline ll get_max(int l, int r, int lq, int rq, int v){ //cout << "hey getting max! " << endl; if(rq <= l || r <= lq) return -1 * inf; if(lq <= l && r <= rq){ //<< l << ' ' << r << ' ' << seg[v].ans1 << ' ' << seg[v].val1 << ' ' << seg[v].mn << endl; return max(seg[v].ans1, seg[v].ans2); } int mid = (l + r) >> 1; shift(v, l, r); return max(get_max(l, mid, lq, rq, v * 2), get_max(mid, r, lq, rq, v * 2 + 1)); } inline void shift(int v, int l, int r){ int mid = (l + r) >> 1; setmax(l, mid, l, mid, seg[v].mn, seg[v].mx, v * 2); setmax(mid, r, mid, r, seg[v].mn, seg[v].mx, v * 2 + 1); seg[v].mn = seg[v].mx = -1 * inf; return; } int main() { ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0); int n; cin >> n; for(int i = 0; i < n; i++){ cin >> h[i] >> a[i] >> b[i]; eve.pb({i, {0, i}}); eve.pb({i - a[i], {1, i}}); eve.pb({i - b[i] - 1, {2, i}}); } sort(all(eve)); int q; cin >> q; for(int i = 0; i < q; i++){ cin >> l[i] >> r[i]; l[i]--; r[i]--; req.pb(i); } sort(all(req), cmp); // az l bozorg be koochak for(auto i : req){ //cout << "aha " << l[i] << ' ' << eve.size() << ' ' << eve.back().fi << endl; while(!eve.empty() && eve.back().fi >= l[i]){ int ty = eve.back().se.fi, id = eve.back().se.se; eve.pop_back(); if(ty == 0){ setmax(0, n, min(n, id + a[id]), min(n, id + b[id] + 1), -h[id], h[id], 1); setval(0, n, id, -1 * inf, -1 * inf, 1); } if(ty == 1){ setval(0, n, id, h[id], -1 * h[id], 1); } if(ty == 2){ setval(0, n, id, -1 * inf, -1 * inf, 1); } //cout << "after event of " << ty << ' ' << id << ' ' << seg[1].ans1 << ' ' << seg[1].ans2 << endl; } out[i] = get_max(0, n, l[i], r[i] + 1, 1); } for(int i = 0; i < q; i++) cout << (out[i] < 0 ? -1 : out[i]) << '\n'; } /* 20 260055884 2 15 737689751 5 5 575359903 1 15 341907415 14 14 162026576 9 19 55126745 10 19 95712405 11 14 416027186 8 13 370819848 11 14 629309664 4 13 822713895 5 15 390716905 13 17 577166133 8 19 195931195 10 17 377030463 14 17 968486685 11 19 963040581 4 10 566835557 1 12 586336111 6 16 385865831 8 9 1 1 20 */
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