This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll INF = 1e9+7;
const ll MOD = 998244353;
typedef pair<ll,ll> ii;
#define iii pair<ii,ll>
#define f(i,a,b) for(ll i = a;i < b;i++)
#define pb push_back
#define vll vector<ll>
#define F first
#define S second
#define all(x) (x).begin(), (x).end()
///I hope I will get uprating and don't make mistakes
///I will never stop programming
///sqrt(-1) Love C++
///Please don't hack me
///@TheofanisOrfanou Theo830
///Think different approaches (bs,dp,greedy,graphs,shortest paths,mst)
///Stay Calm
///Look for special cases
///Beware of overflow and array bounds
///Think the problem backwards
///Training
bool check(vll a){
ll sum = a[0] + a.back();
ll n = a.size();
f(j,0,n){
if(sum != (a[j] + a[n - j - 1])){
return false;
}
}
return true;
}
int main(void){
ios_base::sync_with_stdio(0);
cin.tie(0);
ll n,k;
cin>>n>>k;
ll arr[n+k];
vll a;
f(i,0,n+k){
cin>>arr[i];
a.pb(arr[i]);
}
vll ans;
a.pop_back();
if(check(a)){
ans = a;
}
a.pb(arr[n+k-1]);
a.erase(a.begin());
if(check(a)){
ans = a;
}
ll sum = a[0] + a.back();
a.insert(a.begin(),arr[0]);
f(j,1,(n+k)/2){
if(a[j] + a[n+k-j-1] != sum){
if(ans.empty()){
if(a[j+1] + a[n+k-j-1] == sum){
a.erase(a.begin() + j);
}
else{
a.erase(a.begin()+n+k-j-1);
}
}
}
}
for(auto x:ans){
cout<<x<<" ";
}
}
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