Submission #514187

#TimeUsernameProblemLanguageResultExecution timeMemory
514187NghesCommuter Pass (JOI18_commuter_pass)C++14
100 / 100
266 ms23292 KiB
#include <iostream>
#include <algorithm>
#include <numeric>
#include <vector>
#include <queue>
#include <tuple>

template <class T>
using MinHeap = std::priority_queue<T, std::vector<T>, std::greater<T>>;

using lint = long long;
constexpr lint INF = 1LL << 50;

struct Edge {
    int dst;
    lint cost;
    explicit Edge(int dst, lint cost) : dst(dst), cost(cost) {}
};

using Graph = std::vector<std::vector<Edge>>;

std::vector<lint> dijkstra(const Graph& graph, int r) {
    std::vector<lint> dist(graph.size(), INF);
    dist[r] = 0;
    MinHeap<std::pair<lint, int>> que;
    que.emplace(dist[r], r);

    while (!que.empty()) {
        lint d;
        int v;
        std::tie(d, v) = que.top();
        que.pop();
        if (dist[v] < d) continue;

        for (auto e : graph[v]) {
            int u = e.dst;
            lint nd = d + e.cost;
            if (dist[u] > nd) {
                dist[u] = nd;
                que.emplace(nd, u);
            }
        }
    }

    return dist;
}

void solve() {
    int n, m, s, t, a, b;
    std::cin >> n >> m >> s >> t >> a >> b;
    --s, --t, --a, --b;

    Graph graph(n);
    while (m--) {
        int u, v;
        lint c;
        std::cin >> u >> v >> c;
        --u, --v;
        graph[u].emplace_back(v, c);
        graph[v].emplace_back(u, c);
    }

    auto ds = dijkstra(graph, s),
         da = dijkstra(graph, a),
         db = dijkstra(graph, b);

    std::vector<int> vs(n);
    std::iota(vs.begin(), vs.end(), 0);
    std::sort(vs.begin(), vs.end(),
              [&](int u, int v) { return ds[u] < ds[v]; });

    std::vector<std::vector<lint>>
        dist(3, std::vector<lint>(n, INF));

    for (auto v : vs) {
        dist[0][v] = da[v];
        dist[1][v] = db[v];
        dist[2][v] = da[v] + db[v];

        for (auto e : graph[v]) {
            int u = e.dst;
            if (ds[u] + e.cost > ds[v]) continue;
            for (int k = 0; k < 3; ++k) {
                dist[k][v] = std::min(dist[k][v], dist[k][u]);
            }
        }

        dist[2][v] = std::min({dist[2][v],
                               dist[0][v] + db[v],
                               dist[1][v] + da[v]});
    }

    std::cout << std::min(da[b], dist[2][t]) << std::endl;
}

int main() {
    std::cin.tie(nullptr);
    std::cout.tie(nullptr);
    std::ios::sync_with_stdio(false);

    solve();

    return 0;
}
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