제출 #511852

#제출 시각아이디문제언어결과실행 시간메모리
511852MonarchuwuChase (CEOI17_chase)C++17
30 / 100
215 ms173400 KiB
#include<iostream> #include<algorithm> #include<vector> using namespace std; typedef long long ll; const int N = 1e5 + 9, K = 100 + 2; int n, V; int p[N]; vector<int> g[N]; ll sum_p[N]; ll ans(0); ll dp1[N][K]; // dp1[u][j]: đang ở u , có prenode = par, đã dùng j lượt ll dp2[N][K]; // dp2[u][j]: nhảy 1 lượt đến par, có prenode = u , sẽ dùng j lượt void dfs(int u, int par) { for (int j = 0; j < V; ++j) { ans = max(ans, dp1[u][j + 1]); ans = max(ans, dp2[u][j] + sum_p[u]); } for (int v : g[u]) if (v != par) { for (int j = 1; j <= V; ++j) dp2[v][j] = max(dp2[u][j], dp2[u][j - 1] + sum_p[u] - p[v]); } for (int v : g[u]) if (v != par) { for (int j = 1; j <= V; ++j) { dp1[v][j] = max(dp1[u][j], dp1[u][j - 1] + sum_p[u] - p[par]); } dfs(v, u); } } int main() { cin.tie(NULL)->sync_with_stdio(false); cin >> n >> V; for (int i = 1; i <= n; ++i) cin >> p[i]; for (int i = 1, u, v; i < n; ++i) { cin >> u >> v; g[u].push_back(v); g[v].push_back(u); } for (int u = 1; u <= n; ++u) for (int v : g[u]) sum_p[u] += p[v]; dfs(1, 0); cout << ans << '\n'; } /** /\_/\ * (= ._.) * / >0 \>1 **/ /* ==================================================+ INPUT: | --------------------------------------------------| 12 2 2 3 3 8 1 5 6 7 8 3 5 4 2 1 2 7 3 4 4 7 7 6 5 6 6 8 6 9 7 10 10 11 10 12 --------------------------------------------------| ==================================================+ OUTPUT: | --------------------------------------------------| 36 --------------------------------------------------| ==================================================+ */
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