Submission #511195

#	Time	Username	Problem	Language	Result	Execution time	Memory
511195		alextodoran	Miners (IOI07_miners)	C++17	100 / 100	906 ms	101188 KiB

miners

/**
 ____ ____ ____ ____ ____
||a |||t |||o |||d |||o ||
||__|||__|||__|||__|||__||
|/__\|/__\|/__\|/__\|/__\|

**/

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

const int N_MAX = 100000;

int n;

string s;

int a[N_MAX + 2];

int dp[N_MAX + 2][4][4][4][4];

int answer = 0;

void update (int &addr, int val) {
    answer = max(answer, val);
    addr = max(addr, val);
}

int f (int x, int y, int z) {
    int vec[] = {x, y, z};
    sort(vec, vec + 3);
    if (vec[0] == 0) {
        if (vec[1] == 0) {
            return (vec[2] != 0);
        } else {
            return 1 + (vec[1] != vec[2]);
        }
    } else {
        return 1 + (vec[0] != vec[1]) + (vec[1] != vec[2]);
    }
}

int main () {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);

    cin >> n;
    cin >> s;

    for (int i = 1; i <= n; i++) {
        if (s[i - 1] == 'M') {
            a[i] = 1;
        } else if (s[i - 1] == 'B') {
            a[i] = 2;
        } else {
            a[i] = 3;
        }
    }

    for (int i = 0; i <= n; i++) {
        for (int x1 = 0; x1 <= 3; x1++) {
            for (int y1 = 0; y1 <= 3; y1++) {
                for (int x2 = 0; x2 <= 3; x2++) {
                    for (int y2 = 0; y2 <= 3; y2++) {
                        dp[i][x1][y1][x2][y2] = INT_MIN;
                    }
                }
            }
        }
    }
    dp[0][0][0][0][0] = 0;
    for (int i = 0; i < n; i++) {
        for (int x1 = 0; x1 <= 3; x1++) {
            for (int y1 = 0; y1 <= 3; y1++) {
                for (int x2 = 0; x2 <= 3; x2++) {
                    for (int y2 = 0; y2 <= 3; y2++) {
                        int z = a[i + 1];
                        update(dp[i + 1][y1][z][x2][y2],
                               dp[i][x1][y1][x2][y2] + f(x1, y1, z));
                        update(dp[i + 1][x1][y1][y2][z],
                               dp[i][x1][y1][x2][y2] + f(x2, y2, z));
                    }
                }
            }
        }
    }

    cout << answer << "\n";

    return 0;
}

• Subtask 1: 9 / 9
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 9 / 9
• Subtask 5: 9 / 9
• Subtask 6: 7 / 7
• Subtask 7: 8 / 8
• Subtask 8: 8 / 8
• Subtask 9: 8 / 8
• Subtask 10: 8 / 8
• Subtask 11: 8 / 8
• Subtask 12: 8 / 8