이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
using namespace std;
#include"holiday.h"
#include <iostream>
#include <vector>
#include <algorithm>
#define MAXN 100005
pair<long long,int> add(pair<long long,int> a,pair<long long,int> b) {
return make_pair(a.first + b.first,a.second + b.second);
}
struct node {
node *lp,*rp;
pair<long long,int> v;
node(int l,int r) {
lp = rp = nullptr;
v = make_pair(0,0);
if(l == r) return;
int m = (l + r) >> 1;
lp = new node(l,m);
rp = new node(m + 1,r);
}
node(node *_lp,node *_rp) {
lp = _lp;
rp = _rp;
v = add(lp -> v,rp -> v);
}
node(pair<long long,int> _v) {
v = _v;
}
node* upd(int l,int r,int x,pair<long long,int> d) {
if(l == r) return new node(add(v,d));
int m = (l + r) >> 1;
if(x <= m) return new node(lp -> upd(l,m,x,d),rp);
return new node(lp,rp -> upd(m + 1,r,x,d));
}
pair<long long,int> get(int l,int r,int a,int b) {
if(a > r || b < l) return make_pair(0,0);
if(a <= l && b >= r) return v;
int m = (l + r) >> 1;
return add(lp -> get(l,m,a,b),rp -> get(m + 1,r,a,b));
}
};
node* st[MAXN];
int N,S,D;
pair<long long,int> dp[MAXN];
void solve1(int x,int y,int a,int b) {
if(x > y) return;
int z = (x + y) >> 1;
dp[z] = {-1,-1};
for(int i = a;i <= b;++i) {
int l = 0;
int r = N - 1;
while(l < r) {
int m = (l + r + 1) >> 1;
if(st[m] -> get(0,N - 1,z,i).second + (i - S) + (i - z) <= D) {
l = m;
}else{
r = m - 1;
}
}
dp[z] = max(dp[z],{st[l] -> get(0,N - 1,z,i).first,i});
}
if(x == y) return;
solve1(x,z - 1,a,dp[z].second);
solve1(z + 1,y,dp[z].second,b);
}
void solve2(int x,int y,int a,int b) {
if(x > y) return;
int z = (x + y) >> 1;
if(!dp[z].first) dp[z] = {-1,-1};
for(int i = a;i <= b;++i) {
int l = 0;
int r = N - 1;
while(l < r) {
int m = (l + r + 1) >> 1;
if(st[m] -> get(0,N - 1,i,z).second + (S - i) + (z - i) <= D) {
l = m;
}else{
r = m - 1;
}
}
dp[z] = max(dp[z],{st[l] -> get(0,N - 1,i,z).first,i});
}
if(x == y) return;
solve2(z + 1,y,a,dp[z].second);
solve2(x,z - 1,dp[z].second,b);
}
long long int findMaxAttraction(int n, int start, int d, int attraction[]) {
N = n;
S = start;
D = d;
vector<pair<long long,int>> v;
for(int i = 0;i < N;++i) {
v.push_back({-attraction[i],i});
}
st[0] = new node(0,N - 1);
sort(v.begin(),v.end());
for(int i = 0;i < N;++i) {
st[i + 1] = st[i] -> upd(0,N - 1,v[i].second,make_pair(-v[i].first,1));
}
solve1(0,S,S,N - 1);
solve2(S,N - 1,0,S);
long long ans = 0;
for(int i = 0;i < N;++i) {
ans = max(ans,dp[i].first);
}
return ans;
}
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