제출 #508800

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
508800		silverfish	악어의 지하 도시 (IOI11_crocodile)	C++17	100 / 100	805 ms	101472 KiB

crocodile

#include <bits/stdc++.h>
#include "crocodile.h"

using namespace std;

/*<DEBUG>*/
#define tem template <typename 
#define can_shift(_X_, ...) enable_if_t<sizeof test<_X_>(0) __VA_ARGS__ 8, debug&> operator<<(T i)
#define _op debug& operator<<
tem C > auto test(C *x) -> decltype(cerr << *x, 0LL);
tem C > char test(...);
tem C > struct itr{C begin, end; };
tem C > itr<C> get_range(C b, C e) { return itr<C>{b, e}; }
struct debug{
#ifdef _LOCAL
	~debug(){ cerr << endl; }
	tem T > can_shift(T, ==){ cerr << boolalpha << i; return *this; }
	tem T> can_shift(T, !=){ return *this << get_range(begin(i), end(i)); }
	tem T, typename U > _op (pair<T, U> i){ 
		return *this << "< " << i.first << " , " << i.second << " >"; }
	tem T> _op (itr<T> i){
		*this <<  "{ ";
		for(auto it = i.begin; it != i.end; it++){
			*this << " , " + (it==i.begin?2:0) << *it;
		}
		return *this << " }";
	}
#else
tem T> _op (const T&) { return *this; }
#endif 
};

tem T>
string _ARR_(T* arr, int sz){
	string ret = "{ " + to_string(arr[0]); 
	for(int i = 1; i < sz; i++) ret += " , " +  to_string(arr[i]);
	ret += " }"; return ret;
}

#define exp(...) " [ " << #__VA_ARGS__ << " : " << (__VA_ARGS__) << " ]"
/*</DEBUG>*/

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef unsigned int uint;
typedef pair<int, int> pii;
//mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

#define pb push_back
#define FAST ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define TC int __TC__; cin >> __TC__; while(__TC__--)
#define ar array

const int N = 100005, INF = 1000000009;

struct edge{
	ll to, w; 
};

ll dp[N], vis[N];
vector<edge> adj[N];

int travel_plan(int n, int m, int r[][2], int l[], int k, int p[])
{
	for(int i = 0; i < m; ++i){
		adj[r[i][0]].pb({r[i][1], l[i]});
		adj[r[i][1]].pb({r[i][0], l[i]});
	}

	fill(dp, dp+n+1, INF);

	priority_queue<ar<ll,2>, vector<ar<ll,2>>, greater<ar<ll,2>>> q;

	for(int i = 0; i < k; ++i){
		vis[p[i]] = 1;
		dp[p[i]] = 0;
		q.push({0, p[i]});
	}

	while(q.size()){
		auto [w, u] = q.top();
		q.pop();

		if(vis[u] == 2) continue;

		if(!vis[u]){
			vis[u] = 1;
			continue;
		}

		if(vis[u] == 1){
			dp[u] = w;
			vis[u] = 2;
		}


		for(auto [v, cw] : adj[u]){
			if(vis[v] != 2) q.push({dp[u] + cw, v});
		}

	}

	return dp[0];
}

• Subtask 1: 46 / 46
• Subtask 2: 43 / 43
• Subtask 3: 11 / 11