제출 #507549

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
507549		silverfish	악어의 지하 도시 (IOI11_crocodile)	C++17	46 / 100	150 ms	262148 KiB

crocodile

#include <bits/stdc++.h>
#include "crocodile.h"

using namespace std;

/*<DEBUG>*/
#define tem template <typename 
#define can_shift(_X_, ...) enable_if_t<sizeof test<_X_>(0) __VA_ARGS__ 8, debug&> operator<<(T i)
#define _op debug& operator<<
tem C > auto test(C *x) -> decltype(cerr << *x, 0LL);
tem C > char test(...);
tem C > struct itr{C begin, end; };
tem C > itr<C> get_range(C b, C e) { return itr<C>{b, e}; }
struct debug{
#ifdef _LOCAL
	~debug(){ cerr << endl; }
	tem T > can_shift(T, ==){ cerr << boolalpha << i; return *this; }
	tem T> can_shift(T, !=){ return *this << get_range(begin(i), end(i)); }
	tem T, typename U > _op (pair<T, U> i){ 
		return *this << "< " << i.first << " , " << i.second << " >"; }
	tem T> _op (itr<T> i){
		*this <<  "{ ";
		for(auto it = i.begin; it != i.end; it++){
			*this << " , " + (it==i.begin?2:0) << *it;
		}
		return *this << " }";
	}
#else
tem T> _op (const T&) { return *this; }
#endif 
};

tem T>
string _ARR_(T* arr, int sz){
	string ret = "{ " + to_string(arr[0]); 
	for(int i = 1; i < sz; i++) ret += " , " +  to_string(arr[i]);
	ret += " }"; return ret;
}

#define exp(...) " [ " << #__VA_ARGS__ << " : " << (__VA_ARGS__) << " ]"
/*</DEBUG>*/

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef unsigned int uint;
typedef pair<int, int> pii;
//mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

#define pb push_back
#define FAST ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define TC int __TC__; cin >> __TC__; while(__TC__--)
#define ar array

const int N = 100005, INF = 1000000009;

int dp[N];
vector<ar<int,2>> adj[N];

void dfs(int u, int p=0){
	ar<int,2> mn = {INF, INF};
	for(auto [v, w] : adj[u]){
		if(v^p){
			dfs(v, u);
			if(dp[v]+w <= mn[0]){
				swap(mn[0], mn[1]);
				mn[0] = dp[v]+w;
			}else mn[1] = min(mn[1], dp[v]+w);
		}
	}
	dp[u] = mn[1];
	if(adj[u].size() == 1) dp[u] = 0;
}

int travel_plan(int n, int m, int r[][2], int l[], int k, int p[])
{
	for(int i = 0; i < m; ++i){
		adj[r[i][0]].pb({r[i][1], l[i]});
		adj[r[i][1]].pb({r[i][0], l[i]});
	}
	dfs(0);
	return dp[0];
}

• Subtask 1: 46 / 46
• Subtask 2: 0 / 43
• Subtask 3: 0 / 11