Submission #507549

#TimeUsernameProblemLanguageResultExecution timeMemory
507549silverfishCrocodile's Underground City (IOI11_crocodile)C++17
46 / 100
150 ms262148 KiB
#include <bits/stdc++.h> #include "crocodile.h" using namespace std; /*<DEBUG>*/ #define tem template <typename #define can_shift(_X_, ...) enable_if_t<sizeof test<_X_>(0) __VA_ARGS__ 8, debug&> operator<<(T i) #define _op debug& operator<< tem C > auto test(C *x) -> decltype(cerr << *x, 0LL); tem C > char test(...); tem C > struct itr{C begin, end; }; tem C > itr<C> get_range(C b, C e) { return itr<C>{b, e}; } struct debug{ #ifdef _LOCAL ~debug(){ cerr << endl; } tem T > can_shift(T, ==){ cerr << boolalpha << i; return *this; } tem T> can_shift(T, !=){ return *this << get_range(begin(i), end(i)); } tem T, typename U > _op (pair<T, U> i){ return *this << "< " << i.first << " , " << i.second << " >"; } tem T> _op (itr<T> i){ *this << "{ "; for(auto it = i.begin; it != i.end; it++){ *this << " , " + (it==i.begin?2:0) << *it; } return *this << " }"; } #else tem T> _op (const T&) { return *this; } #endif }; tem T> string _ARR_(T* arr, int sz){ string ret = "{ " + to_string(arr[0]); for(int i = 1; i < sz; i++) ret += " , " + to_string(arr[i]); ret += " }"; return ret; } #define exp(...) " [ " << #__VA_ARGS__ << " : " << (__VA_ARGS__) << " ]" /*</DEBUG>*/ typedef long long ll; typedef unsigned long long ull; typedef long double ld; typedef unsigned int uint; typedef pair<int, int> pii; //mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); #define pb push_back #define FAST ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define TC int __TC__; cin >> __TC__; while(__TC__--) #define ar array const int N = 100005, INF = 1000000009; int dp[N]; vector<ar<int,2>> adj[N]; void dfs(int u, int p=0){ ar<int,2> mn = {INF, INF}; for(auto [v, w] : adj[u]){ if(v^p){ dfs(v, u); if(dp[v]+w <= mn[0]){ swap(mn[0], mn[1]); mn[0] = dp[v]+w; }else mn[1] = min(mn[1], dp[v]+w); } } dp[u] = mn[1]; if(adj[u].size() == 1) dp[u] = 0; } int travel_plan(int n, int m, int r[][2], int l[], int k, int p[]) { for(int i = 0; i < m; ++i){ adj[r[i][0]].pb({r[i][1], l[i]}); adj[r[i][1]].pb({r[i][0], l[i]}); } dfs(0); return dp[0]; }
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