제출 #504078

#제출 시각아이디문제언어결과실행 시간메모리
504078Carmel_Ab1Linear Garden (IOI08_linear_garden)C++17
20 / 100
1578 ms6072 KiB
/* #pragma GCC target ("avx2") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops") */ #include<bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> //using namespace __gnu_pbds; using namespace std; typedef long double ld; typedef long long ll; typedef unsigned long long ull; typedef vector<int>vi; typedef vector<vector<int>>vvi; typedef vector<ll>vl; typedef vector<vl> vvl; typedef pair<int,int>pi; typedef pair<ll,ll> pl; typedef vector<pl> vpl; typedef vector<ld> vld; typedef pair<ld,ld> pld; typedef vector<pi> vpi; //typedef tree<ll, null_type, less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; template<typename T> ostream& operator<<(ostream& os, vector<T>& a){os<<"[";for(int i=0; i<ll(a.size()); i++){os << a[i] << ((i!=ll(a.size()-1)?" ":""));}os << "]\n"; return os;} #define all(x) x.begin(),x.end() #define YES out("YES") #define NO out("NO") #define out(x){cout << x << "\n"; return;} #define outfl(x){cout << x << endl;return;} #define GLHF ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL) #define print(x){for(auto ait:x) cout << ait << " "; cout << "\n";} #define pb push_back #define umap unordered_map template<typename T1, typename T2> istream& operator>>(istream& is, pair<T1, T2>& p){is >> p.first >> p.second;return is;} template<typename T1, typename T2> ostream& operator<<(ostream& os, pair<T1, T2>& p){os <<"" << p.first << " " << p.second << ""; return os;} void usaco(string taskname){ string fin = taskname + ".in"; string fout = taskname + ".out"; const char* FIN = fin.c_str(); const char* FOUT = fout.c_str(); freopen(FIN, "r", stdin); freopen(FOUT, "w", stdout); } template<typename T> void read(vector<T>& v){ int n=v.size(); for(int i=0; i<n; i++) cin >> v[i]; } template<typename T> vector<T>UNQ(vector<T>a){ vector<T>ans; for(T t:a) if(ans.empty() || t!=ans.back()) ans.push_back(t); return ans; } void solve(); int main(){ GLHF; int t=1; //cin >> t; while(t--) solve(); } bool ok(string s){ int n=s.size(); vi pref(n); for(int i=0; i<n; i++) pref[i]=(i?pref[i-1]:0)+(s[i]=='L'?1:-1); auto sum=[&](int l,int r){ return pref[r]-(l?pref[l-1]:0); }; for(int i=0; i<n; i++) for(int j=i+2; j<n; j++){ if(abs(sum(i,j))>2)return 0; } return 1; } ll calc(string t){ int n=t.size(),ans=0; vector<string>v; for(int i=0; i<(1<<n); i++){ string s; for(int j=0; j<n; j++) if(i&(1<<j)) s+='L'; else s+='P'; if(s<=t && ok(s)) v.pb(s),ans++; } sort(all(v)); //print(v) cout.flush(); return ans; } void solve() { ll n,mod; cin >> n >> mod; string s; cin >> s; out(calc(s)%mod) ll ans=0;//how many are lexic. smaller than s vector<vvl>dp(n+1,vvl(2,vl(2))); dp[1][0][1]=dp[1][1][0]=2; dp[1][0][0]=dp[1][1][1]=1; for(int i=2; i<=n; i++){ for(int c1=0; c1<2; c1++) for(int c2=0; c2<2; c2++){ if(c1!=c2) dp[i][c1][c2]=(dp[i-1][c2][c2]+dp[i-1][c2][c2^1])%mod; else dp[i][c1][c2]=dp[i-1][c2][c2^1]%mod; } } // L < P !!! for(int i=1; i<n; i++){//i is tie-breaker if(s[i]=='L')continue; ans=(ans+dp[n-i-1][1][(s[i-1]=='L')])%mod; } cout << calc(s) << endl; if(s[0]=='P') { ans=(ans+dp[n-2][1][0])%mod; ans=(ans+dp[n-2][1][1])%mod; } ans=(ans+1)%mod; out(ans) } /* 12 100000000 LPLLPLPPLPLL */

컴파일 시 표준 에러 (stderr) 메시지

linear_garden.cpp: In function 'void usaco(std::string)':
linear_garden.cpp:47:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   47 |     freopen(FIN, "r", stdin);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~
linear_garden.cpp:48:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   48 |     freopen(FOUT, "w", stdout);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~
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