| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
|---|---|---|---|---|---|---|---|
| 503074 | lobo_prix | 악어의 지하 도시 (IOI11_crocodile) | C++17 | 0 ms | 0 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define _EXT_CODECVT_SPECIALIZATIONS_H 1
#define _EXT_ENC_FILEBUF_H 1
#include <bits/extc++.h>
using namespace std;
#define int i64
#define FP_EPS 1e-11
#define COUT_FP 11
using f64=double; //long double(살짝느림),__float128(매우느림)
#define CPP20 1
#define ARGAUTO 1
#define DBG_SETW 3
//#define CONCEPT
#define pushb(...) push_back({__VA_ARGS__})
#define pushf(...) push_front({__VA_ARGS__})
#define push_(...) push({__VA_ARGS__})
#define popb pop_back
#define popf pop_front
#define fi first
#define se second
#define mkp make_pair
#define mkt make_tuple
#define cxp constexpr
#define lb lower_bound
#define ub upper_bound
#define bs binary_search
#define reduce accumulate
#define itos to_string
using i64=long long;using u64=unsigned long long;
using pint=pair<int,int>;using tint=tuple<int,int,int>;
template<class T>using Str=basic_string<T>;
template<class T,class CMP=greater<>>using PQ=std::priority_queue<T,vector<T>,CMP>;
#define head(x) (x.begin())
#define tail(x) prev(x.end())
//Handy Funcs
template<class T>int sz(const T& x){return x.size();}
int divc(int a,int b){if(b<0)a=-a,b=-b;return (a>0)?(a+b-1)/b:a/b;}
int divf(int a,int b){if(b<0)a=-a,b=-b;return (a>0)?a/b:(a-b+1)/b;}
cxp i64 lg2f(i64 x){return 63-__builtin_clzll(x);}
cxp i64 lg2c(i64 x){return 64-__builtin_clzll(x-1);}
template<class T>T sq(T x){return x*x;}
void WARN(bool cond,const char* str){
#if DEBUG
static set<const char*> z;
if(cond&&!z.count(str))z.insert(str),cerr<<"[WARN] "<<str<<endl;
#endif
}
template<class T>cxp T inf(){return numeric_limits<T>::max()/2;}
#ifdef CONCEPT
template<typename T> concept MemberInf=requires(T t){t.inf();};
template<MemberInf T>T inf(){return T().inf();}
#endif
template<class T, class P=vector<T>>
struct Arr:public P{
Arr(){P::shrink_to_fit();}
explicit Arr(signed n):P(n){}
explicit Arr(signed n,T init):P(n,init){}
Arr(initializer_list<T>il):P(il){}
#if ARGAUTO
Arr(auto its, auto ite):P(its,ite){}
#endif
inline T& operator[](signed i){
int n=sz(*this);
if(i<0)i+=n,WARN(1,"Neg Index Found");
if(i>=n)i-=n,WARN(1,"Over Index Found");
return P::operator[](i);
}
const T& operator[](signed i)const{
int n=sz(*this);
if(i<0)i+=n,WARN(1,"Neg Index Found");
if(i>=n)i-=n,WARN(1,"Over Index Found");
return P::operator[](i);
}
T& at(signed i){return *this[i];}
const T& at(signed i)const{return *this[i];}
};
#if ARGAUTO
template<class... A> auto ARR(auto n,A&&... a)
{if constexpr(!sizeof...(a)) return n; else return Arr(n,ARR(a...));}
#endif
#define ARG(...) __VA_ARGS__
#define func(RetT,fname,...) function<RetT(__VA_ARGS__)> fname=[&](__VA_ARGS__)->RetT
#define lam(expr,...) [&](__VA_ARGS__){return expr;}
#define lamp(expr,...) [](__VA_ARGS__){return expr;}
template<class T,class U>bool assmin(T& a,U&& b){return a>b?a=b,true:false;}
template<class T,class U>bool assmax(T& a,U&& b){return a<b?a=b,true:false;}
template<class T>int argmin(const Arr<T>& a){return min_element(a.begin(),a.end())-a.begin();}
template<class T>int argmax(const Arr<T>& a){return max_element(a.begin(),a.end())-a.begin();}
// Arr<int> range(int n){Arr<int> r;while(n--)r.pushb(sz(r));return r;} std::iota써라
template<class T>Arr<pair<int,T>> enumer(const Arr<T>& a){//views::enumerate in c++23
Arr<pair<int,T>> r;
for(auto&i:a)r.pushb(sz(r),i);
return r;
}
Arr<int> permuinv(const Arr<int>& a){
Arr<int> r(sz(a));
for(auto [i,v]:enumer(a))r[v]=i;
return r;
}
Arr<Arr<int>> occur(const Arr<int>& a){
Arr<Arr<int>> r(*max_element(a.begin(),a.end()));
for(auto [i,v]:enumer(a))r[v].pushb(i);
return r;
}
//Consts
// const f64 pi=numbers::pi_v<f64>,eps=FP_EPS;
const f64 pi=acos(-1),eps=FP_EPS;
const int dir[4][2]={{1,0},{0,1},{-1,0},{0,-1}};
//Pre-runs
#if !(DEBUG)
auto __PR1=(ios::sync_with_stdio(0),cin.tie(0),cout.tie(0));
#endif
auto& __PR2=(cout<<fixed<<setprecision(COUT_FP));
//
#define FASTIO
//INPUT, strstream으로 더 깔끔하게 가능할까?
struct FastCIN{
static const int SZ=1<<24;
unsigned cnt=0;char a[SZ+1],*p;
FastCIN(){preload();}
void tie(int x){}
int preload(){return cnt=cin.read(p=a,SZ).gcount();}
inline char pop(){if(!cnt)preload(); return cnt>0?cnt--,*p++:0;}
inline char get(){if(!cnt)preload(); return cnt>0?*p:0;}
void ignore_wsc(){while(get()==' '||get()=='\n')pop();}
operator bool(){return get();}
template<class T>FastCIN& operator>>(T& n){ignore_wsc();n=0;char neg=false;if(get()=='-')neg=true,pop();while('0'<=get()&&get()<='9')n=n*10+pop()-'0';if(neg)n*=-1;return *this;}//int,i64,Mod<mod>
FastCIN& operator>>(char& c){ignore_wsc();c=pop();return *this;}
FastCIN& operator>>(string& s){ignore_wsc();s.clear();while(get()!=' '&&get()!='\n'&&get())s.pushb(pop());return *this;}
FastCIN& operator>>(f64& n){ignore_wsc();string s;while(('0'<=get()&&get()<='9')||get()=='.'||get()=='-')s.pushb(pop());n=stod(s);return *this;}
template<class T> FastCIN& operator>>(Arr<T>& a){for(auto& i:a)*this>>i;return *this;}
template<class T,class U> FastCIN& operator>>(pair<T,U>& a){*this>>a.fi>>a.se;return *this;}
}fcin;
#define cin fcin
template<class... A> void _cinread(A&...a){((cin>>(a)),...);}
#define READ(T,...) T __VA_ARGS__;_cinread(__VA_ARGS__);
template<class T> ostream& operator<<(ostream& s,const Arr<T>& a){for(auto i:a)cout<<i<<' ';return s;}
template<class T> ostream& operator<<(ostream& o,const pair<T,T>& x){return o<<x.fi<<' '<<x.se;}
template<class... A> void PRINT(A...a){((cout<<a<<' '),...,(cout<<endl));}
//
//Don't use it at interactive
#define endl '\n'
void solve(){
int n,m,k; cin>>n>>m>>k;
Arr<Arr<pint>> g(n);
for(int i=0;i<m;i++){
int u,v,w; cin>>u>>v>>w;
g[u].pushb(v,w);
g[v].pushb(u,w);
}
Arr<int> o(k); for(auto&i:o)cin>>i;
auto d=ARR(n,2,inf<int>());
PQ<pint> pq;
for(auto i:o){
pq.emplace(d[i][0]=0,i);
pq.emplace(d[i][1]=0,i);
}
while(sz(pq)){
auto [dx,x]=pq.top();pq.pop();
// if(dx!=d[x][1])//최단경로는 블록당하므로 두번째최단경로만 expand. 단, d[i][0]과 d[i][1]이 같을 수 있으므로 이 조건외에도 한번 무조건 빼기 위해 vis를 사용하는것. 안빼면 계속 같은길이인 최단경로 많아져서 두번쨰최단경로가 최단경로와 길이가 달라야하는곳에서도 같아지는 반례가 있음.
// continue;
if(dx!=d[x][1] or dx==d[x][0]){
d[x][0]=-1;
continue;
}
for(auto [y,w]:g[x])
if(d[y][1]>dx+w){
d[y][1]=dx+w;
if(d[y][0]>d[y][1])
swap(d[y][0],d[y][1]);
pq.emplace(dx+w,y);
}
}
//cout<<d<<endl;
cout<<d[0][1]<<endl;
}
signed main(){
// int ti=0,t;cin>>t;
// while(++ti<=t)
// cout<<"Case #"<<ti<<": ",
solve();
}