이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define pb push_back
#define all(v) v.begin(),v.end()
#define ff first
#define ss second
using namespace std;
typedef long long ll;
typedef pair<long long, long long> pll;
typedef pair < int, int > pii;
typedef vector<int> vi;
typedef vector<long long> vll;
const int N = 250000 / 2 + 1;
const ll mod = 250001;
void solve(){
int n;
cin >> n;
int a[n], x = 0;
bitset<N> can;
bool ok = 0, okk = 0;
for(int i = 0; i < n; i++) {
cin >> a[i];
if(a[i] % 2)ok = 1;
else okk = 1;
x += a[i];
}
bitset<mod> hv;
hv[0] = 1;
for(int j = 0; j < n; j++) {
hv |= (hv << a[j]);
}
if(x % 2 || !hv[x / 2] || ok & okk) {
cout << "0";
return;
}
x -= a[0];
if(x % 2)ok = 1;
else ok = 0;
x += a[0];
for(int i = 0; i < N; i++) can[i] = 1;
sort(a, a + n);
for(int i = 0; i < n; i++) {
if(i && a[i] == a[i - 1])continue;
hv.reset();
hv[0] = 1;
for(int j = 0; j < n; j++) {
if(j == i)continue;
hv |= (hv << a[j]);
}
x -= a[i];
for(int p = can._Find_first(); p != can.size(); p = can._Find_next(p)) {
int t = p * 2 + ok;
if(!hv[(x + t) / 2] && ((x + t) / 2 - t < 0 || !hv[(x + t) / 2 - t])) can[p] = 0;
}
x += a[i];
}
cout << can.count() << '\n';
for(int p = can._Find_first(); p != can.size(); p = can._Find_next(p)) {
cout << p * 2 + ok << ' ';
}
}
int main() {
//freopen("input.txt", "r", stdin);
//freopen("output.txt", "w", stdout);
ios_base::sync_with_stdio(false);
cin.tie(0);
int times = 1;
//cin >> times;
while(times--)solve();
return 0;
}
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