제출 #502076

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
502076		reo111	Money (IZhO17_money)	C++17	100 / 100	1078 ms	55856 KiB

money

//#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,O3")
//Ofast, avx, avx2, fma
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")

#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")

#include <bits/stdc++.h>

/*#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;*/

#define F first
#define S second
#define mp make_pair
#define pb push_back

#define sz(a) int(a.size())
#define all(a) a.begin(), a.end()
#define bpc(a) __builtin_popcount(a)
#define bpcll(a) __builtin_popcountll(a)
#define wtc(a) cerr << (#a) << " = " << a << '\n'
#define setprec(a) cout.precision(a)
#define base ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define file(a) freopen(a".in", "r", stdin); freopen(a".out", "w", stdout);

#define GET4_(a, b, c, d, ...) d
#define FOR_(i, a, b) for (int i = a; i < b; ++i)
#define FOR1(a) FOR_(i, 0, a)
#define FOR2(i, a) FOR_(i, 0, a)
#define FOR3(i, a, b) FOR_(i, a, b)
#define FORC_(...) GET4_(__VA_ARGS__, FOR3, FOR2, FOR1)
#define FOR(...) FORC_(__VA_ARGS__)(__VA_ARGS__)
#define TRV(i, a) for(auto &i : a)

using namespace std;

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pii> vpi;
typedef vector<pll> vpl;
template <class T> using VC = vector<T>;
template <class T, class V> using PR = pair<T, V>;

//template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
//insert(), find_by_order(), order_of_key(), find(), erase(find())*/

template <class T> bool mns(T &a, T b) {return (a > b ? a = b, 1 : 0);}
template <class T> bool mxs(T &a, T b) {return (a < b ? a = b, 1 : 0);}

pii DR[] = {{-1, 0}, {0, 1}, {1, 0}, {0, -1}, {1, 1}, {1, -1}, {-1, 1}, {-1, -1}};
const int INF = 1e9 + 1e7 + 7;
const int MOD = 1e9 + 7;//998244353;//1e9 + 7;
const ll INFLL = 1e18 + 1e16 + 7ll;
const int N = 1e6 + 5;
const int SS = 5e5 + 5; //rank
const int cs = 850;

void Main();
void precalc();

int main() {
    base//d
    //precalc();
    //setprec(10);
    int T = 1;
    //cin >> T;
    FOR(i, 1, T + 1) {
        //cout << "Case #" << i << ": ";
        Main();
    }
    return 0;
}

int n, a[N];

void Main() {
    cin >> n;
    FOR(n) {
        cin >> a[i];
    }
    int ans = 0;
    set<int> s;
    FOR(n) {
        ++ans;
        if (i == n - 1) {continue; break;}
        auto r = s.upper_bound(a[i]);
        int rv;
        if (r == s.end()) {
            rv = INF;
        } else {
            rv = *r;
        }
        //cout << i << ' ' << rv << endl;
        s.insert(a[i]);
        while (i < n - 1 && a[i] <= a[i + 1] && a[i + 1] <= rv) s.insert(a[++i]);
    }
    cout << ans;
}

• Subtask 1: 9 / 9
• Subtask 2: 16 / 16
• Subtask 3: 20 / 20
• Subtask 4: 55 / 55