제출 #500551

#	제출 시각UTC-0	아이디	문제	언어	결과	실행 시간	메모리
500551	2021-12-31 10:42:21	codr0	Snake Escaping (JOI18_snake_escaping)	C++14	100 / 100	1499 ms	52260 KiB

snake_escaping

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#include <bits/stdc++.h>
#pragma GCC optimize("Ofast,O3")
#define FOR(i,a,b) for(int i=a;i<=b;i++)
#define FORR(i,a,b) for(int i=a;i>=b;i--)
#define S second
#define F first
#define pb push_back
#define SZ(x) (int)x.size()
#define all(x) x.begin(),x.end()
#define err(x) cout<<#x<<": "<<x<<'\n';
 
using namespace std;
const int Q=1e6+4;
const int N=1050000;
int ans[Q];
int A[N];
char qu[Q][21];
int l,q;
int n;
int pw[21];
int Lg[N];
int F[N];
  void solve(){
    FOR(i,0,n-1) F[i]=A[i];
    FOR(i,0,l-1) FOR(msk,0,n-1)
    if(msk&pw[i]) F[msk]+=F[msk^pw[i]];
    int dp0[N];
    FOR(i,0,n-1) dp0[i]=F[i^(n-1)];
    FOR(i,0,q-1) if(ans[i]==-1){
 
 
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컴파일 시 표준 에러 (stderr) 메시지

snake_escaping.cpp: In function 'int32_t main()':
snake_escaping.cpp:3:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
    3 | #define FOR(i,a,b) for(int i=a;i<=b;i++)
      |                    ^~~
snake_escaping.cpp:78:2: note: in expansion of macro 'FOR'
   78 |  FOR(i,0,n-1) A[i]=getchar()-'0'; getchar();
      |  ^~~
snake_escaping.cpp:78:35: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   78 |  FOR(i,0,n-1) A[i]=getchar()-'0'; getchar();
      |                                   ^~~~~~~

• Subtask 1: 5 / 5
• Subtask 2: 7 / 7
• Subtask 3: 10 / 10
• Subtask 4: 53 / 53
• Subtask 5: 25 / 25