Submission #500551

#TimeUTC-0UsernameProblemLanguageResultExecution timeMemory
5005512021-12-31 10:42:21codr0Snake Escaping (JOI18_snake_escaping)C++14
100 / 100
1499 ms52260 KiB
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast,O3")
#define FOR(i,a,b) for(int i=a;i<=b;i++)
#define FORR(i,a,b) for(int i=a;i>=b;i--)
#define S second
#define F first
#define pb push_back
#define SZ(x) (int)x.size()
#define all(x) x.begin(),x.end()
#define err(x) cout<<#x<<": "<<x<<'\n';
using namespace std;
const int Q=1e6+4;
const int N=1050000;
int ans[Q];
int A[N];
char qu[Q][21];
int l,q;
int n;
int pw[21];
int Lg[N];
int F[N];
void solve(){
FOR(i,0,n-1) F[i]=A[i];
FOR(i,0,l-1) FOR(msk,0,n-1)
if(msk&pw[i]) F[msk]+=F[msk^pw[i]];
int dp0[N];
FOR(i,0,n-1) dp0[i]=F[i^(n-1)];
FOR(i,0,q-1) if(ans[i]==-1){
 
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Compilation message (stderr)

snake_escaping.cpp: In function 'int32_t main()':
snake_escaping.cpp:3:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
    3 | #define FOR(i,a,b) for(int i=a;i<=b;i++)
      |                    ^~~
snake_escaping.cpp:78:2: note: in expansion of macro 'FOR'
   78 |  FOR(i,0,n-1) A[i]=getchar()-'0'; getchar();
      |  ^~~
snake_escaping.cpp:78:35: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   78 |  FOR(i,0,n-1) A[i]=getchar()-'0'; getchar();
      |                                   ^~~~~~~
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