#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 100001;
int N,R,dist[1001],pre[1001];
bitset<1001> nex, ADJ[1001];
vi adj[1001], tmp[1001];
int comp[1001];
void finish(int x, int a1, int a2) {
FOR(i,1,N+1) dist[i] = MOD;
queue<int> q; q.push(a1); dist[a1] = 0;
while (sz(q)) {
int t = q.front(); q.pop();
if (t == x || (nex[t] && t != a1 && t != a2)) continue;
for (int j: adj[t]) if (j <= x) {
if (dist[j] != MOD) continue;
dist[j] = dist[t] + 1;
pre[j] = t;
q.push(j);
}
}
vi z;
while (a2 != a1) {
z.pb(a2);
a2 = pre[a2];
}
z.pb(a1);
z.pb(x);
for (int i: z) cout << i << " ";
exit(0);
}
void dfs(int x, int lab, int mx) {
if (comp[x]) return;
comp[x] = lab;
for (int i: adj[x])
if (i < mx && !(nex[x] && nex[i]))
dfs(i,lab,mx);
}
void test(int x) {
FOR(i,1,N+1) comp[i] = 0, nex[i] = 0, tmp[i].clear();
FOR(i,1,x) if (ADJ[x][i]) nex[i] = 1;
FOR(i,1,x) if (nex[i]) {
if (!comp[i]) dfs(i,i,x);
tmp[comp[i]].pb(i);
}
FOR(i,1,x) F0R(j,sz(tmp[i])) FOR(k,j+1,sz(tmp[i]))
if (!ADJ[tmp[i][j]][tmp[i][k]])
finish(x,tmp[i][j],tmp[i][k]);
}
int main() {
ios_base::sync_with_stdio(0); cin.tie(0);
cin >> N >> R;
F0R(i,R) {
int x,y; cin >> x >> y;
adj[x].pb(y), adj[y].pb(x);
ADJ[x][y] = ADJ[y][x] = 1;
}
FORd(i,1,N+1) test(i);
cout << "no";
}
// read the question correctly (is y a vowel? what are the exact constraints?)
// look out for SPECIAL CASES (n=1?) and overflow (ll vs int?)
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
2 ms |
380 KB |
Output is correct |
2 |
Correct |
2 ms |
488 KB |
Output is correct |
3 |
Correct |
2 ms |
488 KB |
Output is correct |
4 |
Correct |
3 ms |
488 KB |
Output is correct |
5 |
Correct |
2 ms |
488 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
2 ms |
488 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
1093 ms |
526096 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
2 ms |
526096 KB |
Output is correct |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
1090 ms |
526096 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
9 ms |
526096 KB |
Output is correct |
2 |
Correct |
6 ms |
526096 KB |
Output is correct |
3 |
Correct |
5 ms |
526096 KB |
Output is correct |
4 |
Execution timed out |
1079 ms |
526364 KB |
Time limit exceeded |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
1104 ms |
526364 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
1093 ms |
526900 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Execution timed out |
1101 ms |
526900 KB |
Time limit exceeded |
2 |
Halted |
0 ms |
0 KB |
- |
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
24 ms |
526900 KB |
Output is correct |
2 |
Correct |
166 ms |
526900 KB |
Output is correct |
3 |
Execution timed out |
1099 ms |
526988 KB |
Time limit exceeded |
4 |
Halted |
0 ms |
0 KB |
- |