제출 #500200

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
500200		armashka	은행 (IZhO14_bank)	C++17	19 / 100	109 ms	536 KiB

bank

#include <bits/stdc++.h>
 
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
 
#define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);
#define all(v) v.begin(),v.end()
#define pb push_back
#define sz size()
#define ft first
#define sd second
 
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef unsigned long long ull;
 
const int N = 1e5 + 5;
const ll M = 1e8;
const ll inf = 1e18;
const ll mod = 1e9;
const double Pi = acos(-1); 
 
ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); }
bool odd(ll n) { return (n % 2 == 1); }
bool even(ll n) { return (n % 2 == 0); }            

ll n, m, a[25], b[25];
vector <ll> v[25];
bool used[N];

void dfs(ll vv, ll dis) {
	int to = vv + 1;
	used[vv] = 1;
	for (auto x : v[to]) {
		ll next = dis ^ x;
		if (__builtin_popcount(next) ==__builtin_popcount(dis) + __builtin_popcount(next)) {
			//cout << vv << " " << to << "-> " << dis << "\n";
			dfs(to, dis + x);
		}
	}
}

const void solve(/*Armashka*/) {
	cin >> n >> m;
	for (int i = 1; i <= n; ++ i) cin >> a[i];
	for (int j = 1; j <= m; ++ j) cin >> b[j];
	for (int mask = 0; mask < (1 << (m + 1)); ++ mask) {
		ll sum = 0;
		for (int i = 1; i <= m; ++ i) {
			if (mask & (1 << i)) sum += b[i];
		}
		for (int i = 1; i <= n; ++ i) {
			if (sum == a[i]) v[i].pb(mask);
		}
	}
	for (auto x : v[1]) {
		dfs(1, x);
	}
	/*for (int i = 1; i <= n; ++ i) {
		for (auto x : v[i]) cout << x << " ";
		cout << "\n";
	}*/
	if (used[n]) cout << "YES\n";
	else cout << "NO\n";
}
            
signed main() {
    fast;
    //freopen("threesum.in", "r", stdin);
    //freopen("threesum.out", "w", stdout);
    int tt = 1;
    //cin >> tt;
    while (tt --) {                                                             
        solve();
    }
}

• Subtask 1: 19 / 19
• Subtask 2: 0 / 25
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29