제출 #500148

#제출 시각아이디문제언어결과실행 시간메모리
500148inksamuraiPutovanje (COCI20_putovanje)C++17
0 / 110
143 ms37224 KiB
#include <bits/stdc++.h> #define fi first #define se second #define pb push_back #define sz(a) (int)a.size() #define all(a) a.begin(),a.end() #define rep(i,n) for(int i=0;i<n;i++) #define crep(i,x,n) for(int i=x;i<n;i++) #define drep(i,n) for(int i=n-1;i>=0;i--) #define vec(...) vector<__VA_ARGS__> #define _3qplfh5 ios_base::sync_with_stdio(false),cin.tie(0),cout.tie(0) using namespace std; typedef long long ll; typedef long double ld; using pii=pair<int,int>; using vi=vector<int>; using vll=vector<long long>; struct treelca{ int n; int timer=0; vec(vi) adj; vi tin,tout,tour,tourid; vi segtree; vi depth; treelca(int m,int root,vec(vi) neadj){ init(m,root,neadj); } void init(int m,int root,vec(vi) neadj){ n=m; tin.clear(); tout.clear(); tour.clear(); tourid.clear(); depth.clear(); tin.resize(n,0); tout.resize(n,0); tourid.resize(n,0); depth.resize(n,0); adj=neadj; dfs(root,-1); segtree.resize(4*sz(tour)); build(1,0,sz(tour)-1); } void dfs(int v,int par){ tour.pb(v); tourid[v]=sz(tour)-1; tin[v]=timer++; for(auto u : adj[v]){ if(u==par) continue; depth[u]=depth[v]+1; dfs(u,v); tour.pb(v); } tout[v]=timer++; } void build(int node,int l,int r){ if(l==r){ segtree[node]=tour[l]; }else{ int m=(l+r)>>1; build(node*2,l,m); build(node*2+1,m+1,r); segtree[node]=(tin[segtree[node*2]]<tin[segtree[node*2+1]]?segtree[node*2]:segtree[node*2+1]); } } int query(int node,int l,int r,int _l,int _r){ if(l>_r or r<_l) return -1; if(l>=_l and r<=_r) return segtree[node]; int m=(l+r)>>1; int vl=query(node*2,l,m,_l,_r); int vr=query(node*2+1,m+1,r,_l,_r); if(min(vl,vr)==-1) return max(vl,vr); return (tin[vl]<tin[vr]?vl:vr); } int ancestor(int from,int to){ int tinfrom=tin[from],tinto=tin[to]; if(tinfrom>tinto) swap(tinfrom,tinto); return query(1,0,sz(tour)-1,tinfrom,tinto); } int dist(int u,int v){ return depth[u]+depth[v]-depth[ancestor(u,v)]*2; } }; int main(){ _3qplfh5; int n; cin>>n; using tupiii=tuple<int,int,int>; vec(vec(tupiii)) adj(n); vec(vi) gadj(n); rep(i,n-1){ int u,v,c1,c2; cin>>u>>v>>c1>>c2; u--,v--; adj[u].pb({v,c1,c2}); adj[v].pb({u,c1,c2}); gadj[u].pb(v); gadj[v].pb(u); } treelca lca(n,0,gadj); vi psum(n,0); crep(v,1,n){ int up=lca.ancestor(v,v-1); psum[up]--; psum[v]++; psum[v-1]++; } int ans=0; auto dfs=[&](auto self,int v,int par)->void{ for(auto ed : adj[v]){ auto [u,c1,c2]=ed; if(u!=par){ self(self,u,v); ans+=min(c1*psum[u],c2); psum[v]+=psum[u]; } } }; dfs(dfs,0,-1); cout<<ans<<"\n"; // return 0; }
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