제출 #500014

#제출 시각아이디문제언어결과실행 시간메모리
500014Carmel_Ab1수열 (APIO14_sequence)C++17
33 / 100
527 ms131076 KiB
/* #pragma GCC target ("avx2") #pragma GCC optimization ("O3") #pragma GCC optimization ("unroll-loops") */ #include<bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> //using namespace __gnu_pbds; using namespace std; typedef long double ld; typedef long long ll; typedef unsigned long long ull; typedef vector<int>vi; typedef vector<vector<int>>vvi; typedef vector<ll>vl; typedef vector<vl> vvl; typedef pair<int,int>pi; typedef pair<ll,ll> pl; typedef vector<pl> vpl; typedef vector<ld> vld; typedef pair<ld,ld> pld; typedef vector<pi> vpi; //typedef tree<ll, null_type, less_equal<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; template<typename T> ostream& operator<<(ostream& os, vector<T>& a){os<<"[";for(int i=0; i<ll(a.size()); i++){os << a[i] << ((i!=ll(a.size()-1)?" ":""));}os << "]\n"; return os;} #define all(x) x.begin(),x.end() #define YES out("YES") #define NO out("NO") #define out(x){cout << x << "\n"; return;} #define outfl(x){cout << x << endl;return;} #define GLHF ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL) #define print(x){for(auto ait:x) cout << ait << " "; cout << "\n";} #define pb push_back #define umap unordered_map template<typename T1, typename T2> istream& operator>>(istream& is, pair<T1, T2>& p){is >> p.first >> p.second;return is;} template<typename T1, typename T2> ostream& operator<<(ostream& os, pair<T1, T2>& p){os <<"" << p.first << " " << p.second << ""; return os;} void usaco(string taskname){ string fin = taskname + ".in"; string fout = taskname + ".out"; const char* FIN = fin.c_str(); const char* FOUT = fout.c_str(); freopen(FIN, "r", stdin); freopen(FOUT, "w", stdout); } template<typename T> void read(vector<T>& v){ int n=v.size(); for(int i=0; i<n; i++) cin >> v[i]; } template<typename T> vector<T>UNQ(vector<T>a){ vector<T>ans; for(T t:a) if(ans.empty() || t!=ans.back()) ans.push_back(t); return ans; } void solve(); int main(){ GLHF; int t=1; //cin >> t; while(t--) solve(); } struct seg{ ll l,r,m; seg* lp=0,*rp=0; vl ln; seg(ll l,ll r):l(l),r(r),m((l+r)/2){ln={ll(-1e9),ll(-1e9),ll(-1e9)};} ll get(vl& v,ll x){return v[0]*x+v[1];} void upd(vl f){ bool lef=get(f,l)>get(ln,m); bool mid=get(f,m)>get(ln,m); if(mid) swap(f,ln); if(l+1==r)return; if(lef!=mid) { if(!lp)lp=new seg(l,m); lp->upd(f); } else { if(!rp)rp=new seg(m,r); rp->upd(f); } } pl qur(ll x) { if (l + 1 == r)return {get(ln,x), ln[2]}; if (x < m) { if (!lp)lp = new seg(l, m); return max(lp->qur(x), {get(ln,x), ln[2]}); } else{ if(!rp)rp=new seg(m,r); return max(rp->qur(x), {get(ln,x), ln[2]}); } } }; void solve() { int n,k; cin >> n >> k; vl a(n+1); for(int i=1; i<=n; i++) cin >> a[i]; vl pref(n+1); for(int i=0; i<=n; i++) pref[i]=(i?pref[i-1]:0)+a[i]; vvl dp(n+1,vl(k+1)),prv(n+1,vl(k+1,1)); vector<seg*>s(k+1); for(int i=0; i<=k; i++) s[i]=new seg(0,1e9); for(int i=1; i<=n; i++) { for (int j = 1; j <= k; j++) { pl p=s[j]->qur(pref[i]); dp[i][j] = p.first,prv[i][j]=p.second; } for(int j=0; j<=k; j++) if (i != n) s[j]->upd({pref[i], -pref[i] * pref[i] + (j?dp[i][j-1]:0),i}); } cout << dp[n][k] << "\n"; int i=n,j=k; vi ans; while(i && j){ ans.pb(prv[i][j]); i=prv[i][j]; j--; } sort(all(ans)); ans=UNQ(ans); print(ans) } /* 7 3 4 1 3 4 0 2 3 */

컴파일 시 표준 에러 (stderr) 메시지

sequence.cpp: In function 'void usaco(std::string)':
sequence.cpp:47:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   47 |     freopen(FIN, "r", stdin);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~
sequence.cpp:48:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   48 |     freopen(FOUT, "w", stdout);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~
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