이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,avx")
#include <bits/stdc++.h>
#define int int64_t
using namespace std;
vector<vector<int>> res;
int cnt;
void fillBoarder(int n, int m, int offset) {
for (int i = offset; i<n+offset; i++) {
res[i][offset] = cnt;
res[i][offset+m-1] = cnt;
}
for (int i = offset; i<m+offset; i++) {
res[offset][i] = cnt;
res[offset+n-1][i] = cnt;
}
cnt++;
}
void fillSmaller(int n, int m, int offset) {
if (n>=m) {
for (int i = offset; i<m+offset-1; i+=2) {
res[n+offset-1][i] = cnt;
res[n+offset-1][i+1] = cnt;
res[n+offset-2][i] = cnt;
res[n+offset-2][i+1] = cnt;
cnt++;
}
}
else {
for (int i = offset; i<n+offset-1; i+=2) {
res[i][m+offset-1] = cnt;
res[i+1][m+offset-1] = cnt;
res[i][m+offset-2] = cnt;
res[i+1][m+offset-2] = cnt;
cnt++;
}
}
}
bool solve(int n, int m, int k) {
cnt = 1;
// res.clear();
res.assign(n, vector<int>(m));
if (n%2 || m%2) return 0;
if (k > (n*m)/4) return 0;
if ((n*m)/4 - k == 1) return 0;
if (k < (n*m/4)/(min(n, m)/2)) return 0;
int offset = 0;
while (n != 0 && m != 0) {
if ((n*2 + (m-2)*2)/4 <= n*m/4 - k + 1) {
// cout << "Border\n";
fillBoarder(n, m, offset);
offset++;
k--;
n-=2;
m-=2;
}
else {
// cout << "Edge\n";
fillSmaller(n, m, offset);
k-=min(n, m)/2;
if (n>=m) n-=2;
else m-=2;
}
// for (auto i: res) {
// for (int j: i) {
// cout << j << " ";
// }
// cout << "\n";
// } cout << "\n";
}
return 1;
}
signed main() {
cin.tie(0);
ios_base::sync_with_stdio(0);
int t; cin >> t;
for (int tc = 0; tc < t; tc++) {
int n, m, k; cin >> n >> m >> k;
bool ok = solve(n, m, k);
if (!ok) {
cout << "NO\n";
continue;
}
cout << "YES\n";
for (auto i: res) {
for (int j: i) {
cout << j << " ";
}
cout << "\n";
}
}
// vector<vector<int>> test(8, vector<int>(6));
// int cnt = 1;
// fillout(cnt, test, 2, 8, 0);
// for (auto i: test) {
// for (int j: i) {
// cerr << j << " ";
// }
// cerr << "\n";
// }
return 0;
}
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