Submission #498323

#TimeUsernameProblemLanguageResultExecution timeMemory
498323armashkaSure Bet (CEOI17_sure)C++17
0 / 100
0 ms204 KiB
#include <bits/stdc++.h> //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr); #define all(v) v.begin(),v.end() #define pb push_back #define sz size() #define ft first #define sd second using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef unsigned long long ull; const int N = 1e6 + 5; const ll M = 1e8; const ll inf = 1e18; const ll mod = 1e9; const double Pi = acos(-1); ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;} ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;} ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); } bool odd(ll n) { return (n % 2 == 1); } bool even(ll n) { return (n % 2 == 0); } ll n; double a[N], b[N]; const void solve(/*Armashka*/) { cin >> n; for (int i = 1; i <= n; ++ i) cin >> a[i] >> b[i]; sort(a + 1, a + n + 1); reverse(a + 1, a + n + 1); sort(b + 1, b + n + 1); reverse(b + 1, b + n + 1); double ans = 0.0, sum1 = 0.0, sum2 = 0.0; ll l1 = 1, l2 = 1; while (l1 <= n && l2 <= n) { if (l1 > n) { sum2 += b[l2]; double cnt = l1 + l2 - 1; ans = max(ans, min(sum1 - cnt, sum2 - cnt)); ++ l2; } else if (l2 > n) { sum1 += a[l1]; double cnt = l1 + l2 - 1; ans = max(ans, min(sum1 - cnt, sum2 - cnt)); ++ l1; } else { if (fabs(sum1 + a[l1] - sum2) < fabs(sum2 + b[l2] - sum1)) { sum1 += a[l1]; double cnt = l1 + l2 - 1; ans = max(ans, min(sum1 - cnt, sum2 - cnt)); ++ l1; } else { sum2 += b[l2]; double cnt = l1 + l2 - 1; ans = max(ans, min(sum1 - cnt, sum2 - cnt)); ++ l2; } } //cout << sum1 << " " << sum2 << " " << l1 + l2 - 1 << "\n"; } cout << fixed << setprecision(4) << ans << "\n"; } signed main() { fast; //freopen("divide.in", "r", stdin); //freopen("divide.out", "w", stdout); int tt = 1; //cin >> tt; while (tt --) { solve(); } } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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