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제출 #497970

#제출 시각아이디문제언어결과실행 시간메모리
497970abc864197532Hop (COCI21_hop)C++17
110 / 110
52 ms5336 KiB
#include <bits/stdc++.h> using namespace std; #define lli long long int #define mp make_pair #define pb push_back #define eb emplace_back #define pii pair <int, int> #define X first #define Y second #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() void abc() {cout << endl;} template <typename T, typename ...U> void abc(T a, U ...b) { cout << a << ' ', abc(b...); } template <typename T> void printv(T l, T r) { while (l != r) cout << *l << " \n"[++l == r]; } template <typename A, typename B> istream& operator >> (istream& o, pair<A, B> &a) { return o >> a.X >> a.Y; } template <typename A, typename B> ostream& operator << (ostream& o, pair<A, B> a) { return o << '(' << a.X << ", " << a.Y << ')'; } template <typename T> ostream& operator << (ostream& o, vector<T> a) { if (a.empty()) return o << "{}"; bool is = false; for (T i : a) {o << (is ? ' ' : '{'), is = true, o << i;} return o << '}'; } template <typename T> struct vv : vector <vector <T>> { vv(int n, int m, T v) : vector <vector <T>> (n, vector <T>(m, v)) {} vv() {} }; template <typename T> struct vvv : vector <vv <T>> { vvv(int n, int m, int k, T v) : vector <vv <T>> (n, vv <T>(m, k, v)) {} vvv() {} }; #ifdef Doludu #define test(args...) abc("[" + string(#args) + "]", args) #define owo freopen("input.txt", "r", stdin), freopen("output.txt", "w", stdout) #else #define test(args...) void(0) #define owo ios::sync_with_stdio(false); cin.tie(0) #endif const int mod = 1e9 + 7, N = 100010, logN = 17, K = 350, M = N * 40; int main () { owo; int n; cin >> n; vector <lli> a(n); vv <int> dis(n, 3, 0); for (int i = 0; i < n; ++i) cin >> a[i]; vv <int> ans(n, n, 0); for (int i = 1; i < n; ++i) { for (int j = 0; j < i; ++j) if (a[i] % a[j] == 0) { int pt = 0; for (int k = 1; k <= 2; ++k) { if (dis[j][pt] > dis[j][k]) pt = k; } ans[j][i] = pt; dis[i][pt] = max(dis[i][pt], dis[j][pt] + 1); } } for (int j = 1; j < n; ++j) { for (int i = 0; i < j; ++i) cout << ans[i][j] + 1 << ' '; cout << endl; } }
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