이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//я так много думал, что опять попал
#include <bits/stdc++.h>
#define all(x) x.begin(),x.end()
#define pb push_back
#define ppb pop_back
#define pf push_front
#define ppf pop_front
#define f first
#define s second
#define left(v) v + v
#define right(v) v + v + 1
#define ub upper_bound
#define lb lower_bound
#define pll pair<ll,ll>
//17 SEVENTEEN
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
typedef long long ll;
const long double Pi = acos(-1.0);
const ll dx[] = {0,0,1,-1};
const ll dy[] = {1,-1,0,0};
const ll N = (ll) 1e6 + 17;
const ll M = (ll) 5e3 + 69;
const ll inf = (ll) 1e14 + 3;
const ll mod = (ll) 1e9 + 7;
ll sq(ll x) { return x * x; }
ll zxc = 1, a[N], p[N];
pll dp[N];
void solve() {
ll n;
cin >> n;
for(ll i = 1; i <= n; i++) {
cin >> a[i];
p[i] = p[i - 1] + a[i];
dp[i] = {1, p[i]};
}
for(ll i = 2; i <= n; i++) {
for(ll j = 1; j < i; j++) {
if(dp[j].s <= p[i] - p[j]) {
if(dp[j].f + 1 > dp[i].f)
dp[i] = {dp[j].f + 1, p[i] - p[j]};
if(dp[j].f + 1 == dp[i].f && dp[i].s > p[i] - p[j])
dp[i] = {dp[j].f + 1, p[i] - p[j]};
}
// cout << dp[j].s << " " << p[i] - p[j] << "\n";
}
// cout << "\n";
}
// for(ll i = 1; i <= n; i++) {
// cout << dp[i].f << " " << dp[i].s << "\n";
// }
cout << dp[n].f;
}
int main(/*Уверенно*/) {
ios_base::sync_with_stdio(0);
cin.tie(0);
/*
freopen(".in", "r", stdin);
freopen(".out", "w", stdout);
*/
// cin >> zxc;
while(zxc--) {
solve();
}
return 0;
}
// さよならさ いかなくちゃ
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