제출 #497433

#제출 시각아이디문제언어결과실행 시간메모리
497433armashkaBigger segments (IZhO19_segments)C++17
13 / 100
1 ms448 KiB
#include <bits/stdc++.h> //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr); #define all(v) v.begin(),v.end() #define pb push_back #define sz size() #define ft first #define sd second using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef unsigned long long ull; const int N = 1e6 + 5; const ll M = 1e8; const ll inf = 1e18; const ll mod = 1e9; const double Pi = acos(-1); ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;} ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;} ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); } bool odd(ll n) { return (n % 2 == 1); } bool even(ll n) { return (n % 2 == 0); } struct dinamika { ll cnt, sum; } dp[N]; ll n, a[N], pr[N], t[N * 4]; void upd(ll pos, ll val, ll v = 1, ll tl = 1, ll tr = n) { if (tl == tr) { t[v] = val; return; } else { ll tm = (tl + tr) / 2; if (pos <= tm) upd(pos, val, v + v, tl, tm); else upd(pos, val, v + v + 1, tm + 1, tr); t[v] = max(t[v + v], t[v + v + 1]); } } pll get(ll l, ll r, ll v = 1, ll tl = 1, ll tr = n) { if (r < tl || tr < l) return {0, 0}; if (tl == tr) return {t[v], tl}; ll tm = (tl + tr) / 2; pll ans = {0, 0}; if (t[v + v] > t[v + v + 1]) { ans = get(l, r, v + v, tl, tm); if (ans.ft == 0) ans = get(l, r, v + v + 1, tm + 1, tr); } else { ans = get(l, r, v + v + 1, tm + 1, tr); if (ans.ft == 0) ans = get(l, r, v + v, tl, tm); } return ans; } const void solve(/*Armashka*/) { cin >> n; for (int i = 1; i <= n; ++ i) { cin >> a[i]; pr[i] = pr[i - 1] + a[i]; dp[i] = {1, pr[i]}; upd(i, dp[i].cnt); } for (int i = 1; i <= n; ++ i) { ll l = 1, r = i, j = 1; while (l <= r) { ll mid = (l + r) / 2; if (pr[i] - pr[mid - 1] >= dp[mid - 1].sum) l = mid + 1, j = mid; else r = mid - 1; } //cout << j << " "; pll ans = get(1, j - 1); dp[i] = {ans.ft + 1, pr[i] - pr[ans.sd]}; //cout << dp[i].cnt << " "; upd(i, dp[i].cnt); } cout << dp[n].cnt << "\n"; } signed main() { fast; //freopen("divide.in", "r", stdin); //freopen("divide.out", "w", stdout); int tt = 1; //cin >> tt; while (tt --) { solve(); } } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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