Submission #497422

#	Time	Username	Problem	Language	Result	Execution time	Memory
497422		vinnipuh01	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	0 / 100	1008 ms	34892 KiB

sortbooks

#include <iostream>
#include <bits/stdc++.h>
#include <cmath>
#include <algorithm>
#include <vector>
#include <deque>
#include <set>
#include <stack>
#include <string>
#include <map>
#include <queue>

using namespace std;

const long long oo = 1000000000000000000;

long long int  sum, ans = 0, mx = 0, mn = 1000000000, num, pos;


/*
    ViHHiPuh

   (( `'-""``""-'` ))
     )-__-_.._-__-(
   / --- (o _ o) --- \
   \ .-* ( .0. ) *-. /
   _'-. ,_ '=' _, .-'_
  / `;#'#'# - #'#'#;` \
 \_)) -----'#'----- ((_/
      # --------- #
  '# ------- ------ #'
  /..-'# ------- #'-.\
  _\...-\'# -- #'/-.../_
  ((____)- '#' -(____))


    cout << fixed << setprecision(6) << x;


    freopen ( "sum.in", "r", stdin )
*/

struct Node {
	int mn, mx, ans;
	public :
		Node operator + ( Node a ) {
			Node c;
			c.ans = max( ans, a.ans );
			if ( a.mn < mx )
				c.ans = max( c.ans, mx - a.mn );
			c.mn = min( mn, a.mn );
			c.mx = max( mx, a.mx );
			return c;
		}
} t[ 4000001 ], an;

int n, m, a[ 1000001 ];

void build( int v, int tl, int tr ) {
	if ( tl == tr ) {
		t[ v ].mn = a[ tl ];
		t[ v ].mx = a[ tl ];
		t[ v ].ans = 0;
		return;
	}
	int mid = ( tl + tr ) / 2;
	build( v + v, tl, mid );
	build( v + v + 1, mid + 1, tr );
	t[ v ] = t[ v + v ] + t[ v + v + 1 ];
}

void gett( int v, int tl, int tr, int l, int r ) {
	if ( tl > r || tr < l )
		return;
	if ( tl >= l && tr <= r ) {
		an = an + t[ v ];
		return;
	}
	int mid = ( tl + tr ) / 2;
	gett( v + v, tl, mid, l, r );
	gett( v + v + 1, mid + 1, tr, l, r );
}

int main () {
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
	cin >> n >> m;
	for ( int i = 1; i <= n; i ++ ) {
		cin >> a[ i ];
		mn = min( mn, a[ i ] + 0ll );
		sum = max( sum, a[ i ] + 0ll );
	}
	int l, r, x;
	build( 1, 1, n );
	while ( m -- ) {
		cin >> l >> r >> x;
		num = 0;
		gett( 1, 1, n, l, r );
		cout << ( x >= an.ans ) << "\n";
	}
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 9
• Subtask 3: 0 / 13
• Subtask 4: 0 / 17
• Subtask 5: 0 / 30
• Subtask 6: 0 / 23