이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define endl "\n"
#define mp make_pair
#define pb push_back
#define F first
#define S second
#define sz size()
#define rep(i,k,n) for(int i = k ; i <= n ; ++i)
#define per(i,k,n) for(int i = k ; i >= n ; --i)
#define Zymraq() ios_base::sync_with_stdio(0),cin.tie(0),cout.tie(0)
#define all(x) x.begin(),x.end()
#define fr(x) freopen(x".in","r",stdin),freopen(x".out","w",stdout)
#define toqta return 0
#define PERMUTE next_permutation
#define no cout<<"No"<<endl;
#define yes cout<<"Yes"<<endl;
#define a() a + 1, a + n + 1
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef string S;
typedef double ld;
typedef long double lld;
const int N = 1e6 + 17;
const int modd = 1e9 + 7;
const ll INF = 1e18 - 19;
const int P = 37;
const ll NN = 1e7 + 17;
const ld eps = 1e-19;
const double pi = 3.141592653589793238462643383279 ;
bool sortbysec(const pair<int,int> &a, const pair<int,int> &b){
return (a.second < b.second);
}
void pre (ll a) {
cout << fixed << setprecision(a);
return;
}
ll n;
ll x[N], y[N];
ll pos[1000][1000];
ll totalans = 0;
inline void Solution () {
cin >> n;
for (int i = 1; i <= n * 2; ++ i) {
cin >> x[i] >> y[i];
if (x[i] <= n && x[i] > 0 && y[i] <= 2 && y[i] > 0) pos[x[i]][y[i]] ++;
}
for (int i = 1; i <= n * 2; ++ i) {
if (x[i] > 0 && y[i] > 0 && x[i] <= n && y[i] <= 2 && pos[x[i]][y[i]] != 0) continue;
ll mn = INF, new_posx, new_posy;
for (int j = 1; j <= n; ++ j) {
if (!pos[j][1] && mn > abs (x[i] - j) + abs(y[i] - 1)) {
new_posx = j, new_posy = 1;
mn = abs (x[i] - j) + abs (y[i] - 1);
}
if (!pos[j][2] && mn > abs (x[i] - j) + abs (y[i] - 2)) {
new_posx = j, new_posy = 2;
mn = abs (x[i] - j) + abs (y[i] - 2);
}
}
if (mn != INF) {
totalans += mn;
pos[new_posx][new_posy] = 1;
}
}
for (int i = 1; i <= n * 2; ++ i) {
if (x[i] > 0 && y[i] > 0 && x[i] <= n && y[i] <= 2 && pos[x[i]][y[i]] > 1) {
ll mn = INF, new_posx, new_posy;
for (int j = 1; j <= n; ++ j) {
if (!pos[j][1] && mn > abs (x[i] - j) + abs (y[i] - 1)) {
new_posx = j, new_posy = 1;
mn = abs (x[i] - j) + abs (y[i] - 1);
}
if (!pos[j][2] && mn > abs (x[i] - j) + abs (y[i] - 2)) {
new_posx = j, new_posy = 2;
mn = abs (x[i] - j) + abs(y[i] - 2);
}
}
// cout << mn << ' ' << new_posx << ' ' << new_posy << '\n' << x[i] << y[i];
if (mn != INF) {
pos[x[i]][y[i]] --;
totalans += mn;
pos[new_posx][new_posy] = 1;
}
}
}
cout << totalans;
return;
}
int main () {
Zymraq();
Solution ();
exit (0);
}
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