oj.uz

답안 #49685

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
49685 2018-06-02T07:28:53 Z gs13105 새 집 (APIO18_new_home) C++17
0 / 100
 4638 ms 324208 KB 
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cassert>
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <tuple>
#include <iterator>

using namespace std;

const int MAXN = 300000;
const int MAXI = 1048576;
const int INF = 100000000;

int n, k, q, bp;

vector<int> com;
inline int idx(int x)
{
    return (int)(lower_bound(com.begin(), com.end(), x) - com.begin());
}

struct eve
{
    int t, x, d;
    bool operator <(const eve &e) const
    {
        return t != e.t ? t < e.t : d > e.d;
    }
};

struct pos
{
    int c, l, lt, r, rt;
};

vector<eve> arr;
map<int, pos> loc[MAXN + 10];

struct seg
{
    int t1, t2, x, y;
    bool operator <(const seg &e) const
    {
        return x < e.x;
    }
};

vector<seg> sor[2];
void add_seg(int t1, int t2, int x, int y)
{
    if(t1 > t2 || x == y)
        return;

    int nt1 = bp + idx(t1);
    int nt2 = bp + idx(t2 + 1) - 1;
    if(nt1 > nt2)
        return;

    if(y < x)
        sor[0].push_back({ nt1, nt2, y, x });
    else
        sor[1].push_back({ nt1, nt2, INF - y + 1, INF - x + 1 });
}

struct ent
{
    // v0 : dec, v1 : inc, q : query
    // v : { x, y }
    // q : { x, i }
    vector<pair<int, int>> v[2];
    vector<pair<int, int>> q;
};

ent mem[MAXI + 10];

struct que
{
    int l, y, i;
    bool operator <(const que &x) const
    {
        return l < x.l;
    }
};

vector<que> inp;
bool chk[MAXN + 10];
int ans[MAXN + 10];

int main()
{
    //freopen("in", "r", stdin);
    //freopen("out", "w", stdout);

    scanf("%d%d%d", &n, &k, &q);
    for(int i = 0; i < n; i++)
    {
        int x, t, a, b;
        scanf("%d%d%d%d", &x, &t, &a, &b);
        arr.push_back({ a, x, t });
        arr.push_back({ b, x, -t });
    }

    for(int i = 0; i < q; i++)
    {
        int l, y;
        scanf("%d%d", &l, &y);
        inp.push_back({ l, y, i });
        com.push_back(y);
    }

    sort(inp.begin(), inp.end());
    sort(com.begin(), com.end());
    com.erase(unique(com.begin(), com.end()), com.end());

    int sz = (int)com.size();
    for(bp = 1; bp < sz; bp *= 2);

    sort(arr.begin(), arr.end());
    int cur, cnt = 0;
    for(eve &e : arr)
    {
        if(e.d > 0)
        {
            if(loc[e.d].size() == 0)
            {
                cnt++;
                if(cnt == k)
                    cur = e.t;
            }

            auto it = loc[e.d].find(e.x);
            if(it != loc[e.d].end())
            {
                it->second.c++;
                continue;
            }

            it = loc[e.d].insert({ e.x,{ 1, 1, e.t, INF, e.t } }).first;
            pos &p = it->second;

            if(it != loc[e.d].begin())
            {
                int x = prev(it)->first;
                pos &q = prev(it)->second;

                add_seg(q.rt, e.t - 1, x, q.r);
                q.rt = e.t;
                q.r = (x + e.x) / 2;

                p.l = (x + e.x + 1) / 2;
            }

            if(next(it) != loc[e.d].end())
            {
                int x = next(it)->first;
                pos &q = next(it)->second;

                add_seg(q.lt, e.t - 1, x, q.l);
                q.lt = e.t;
                q.l = (x + e.x + 1) / 2;

                p.r = (x + e.x) / 2;
            }
        }
        else
        {
            e.d = -e.d;

            auto it = loc[e.d].find(e.x);
            pos &p = it->second;

            if(p.c > 1)
            {
                p.c--;
                continue;
            }

            add_seg(p.lt, e.t, e.x, p.l);
            add_seg(p.rt, e.t, e.x, p.r);

            if(it != loc[e.d].begin())
            {
                int x = prev(it)->first;
                pos &q = prev(it)->second;

                add_seg(q.rt, e.t, x, q.r);
                q.rt = e.t + 1;
                if(next(it) != loc[e.d].end())
                {
                    int y = next(it)->first;
                    q.r = (x + y) / 2;
                }
                else
                    q.r = INF;
            }

            if(next(it) != loc[e.d].end())
            {
                int x = next(it)->first;
                pos &q = next(it)->second;

                add_seg(q.lt, e.t, x, q.l);
                q.lt = e.t + 1;
                if(it != loc[e.d].begin())
                {
                    int y = prev(it)->first;
                    q.l = (y + x + 1) / 2;
                }
                else
                    q.l = 1;
            }

            loc[e.d].erase(it);

            if(loc[e.d].size() == 0)
            {
                if(cnt == k)
                {
                    int t1 = idx(cur);
                    int t2 = idx(e.t + 1) - 1;
                    for(int i = t1; i <= t2; i++)
                        chk[i] = 1;
                }
                cnt--;
            }
        }
    }

    for(que &e : inp)
    {
        int x = idx(e.y);
        if(chk[x])
        {
            x += bp;
            while(x)
            {
                mem[x].q.push_back({ e.l, e.i });
                x /= 2;
            }
        }
        else
            ans[e.i] = -1;
    }

    for(int i = 0; i < 2; i++)
    {
        sort(sor[i].begin(), sor[i].end());
        for(seg &e : sor[i])
        {
            int t1 = e.t1;
            int t2 = e.t2;
            while(t1 < t2)
            {
                if(t1 % 2 == 1)
                {
                    mem[t1].v[i].push_back({ e.x, e.y });
                    t1++;
                }
                if(t2 % 2 == 0)
                {
                    mem[t2].v[i].push_back({ e.x, e.y });
                    t2--;
                }
                t1 /= 2;
                t2 /= 2;
            }
            if(t1 == t2)
                mem[t1].v[i].push_back({ e.x, e.y });
        }
    }

    for(int x = 1; x <= bp + sz - 1; x++)
    {
        for(int i = 0; i < 2; i++)
        {
            int mx, p1, p2, sz1, sz2;
            mx = p1 = p2 = 0;
            sz1 = (int)mem[x].v[i].size();
            sz2 = (int)mem[x].q.size();
            while(p2 < sz2)
            {
                int qx, qi;
                tie(qx, qi) = mem[x].q[p2];
                if(i == 1)
                    qx = INF - qx + 1;

                if(p1 != sz1 && mem[x].v[i][p1].first <= qx)
                {
                    mx = max(mx, mem[x].v[i][p1].second);
                    p1++;
                }
                else
                {
                    ans[qi] = max(ans[qi], max(0, mx - qx));
                    p2++;
                }
            }
        }
    }

    for(int i = 0; i < q; i++)
        printf("%d\n", ans[i]);
    return 0;
}

Compilation message

new_home.cpp: In function 'int main()':
new_home.cpp:104:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d%d%d", &n, &k, &q);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~~
new_home.cpp:108:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d%d%d%d", &x, &t, &a, &b);
         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~
new_home.cpp:116:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d%d", &l, &y);
         ~~~~~^~~~~~~~~~~~~~~~

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 76 ms 88184 KB Output is correct
2 Correct 79 ms 88280 KB Output is correct
3 Correct 77 ms 88280 KB Output is correct
4 Incorrect 75 ms 88464 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #2
0 / 7.0

# 결과 실행 시간 메모리 Grader output
1 Correct 76 ms 88184 KB Output is correct
2 Correct 79 ms 88280 KB Output is correct
3 Correct 77 ms 88280 KB Output is correct
4 Incorrect 75 ms 88464 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #3
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2101 ms 241480 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 23.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4638 ms 324208 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5
0 / 35.0

# 결과 실행 시간 메모리 Grader output
1 Correct 76 ms 88184 KB Output is correct
2 Correct 79 ms 88280 KB Output is correct
3 Correct 77 ms 88280 KB Output is correct
4 Incorrect 75 ms 88464 KB Output isn't correct
5 Halted 0 ms 0 KB -

Subtask #6
0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 76 ms 88184 KB Output is correct
2 Correct 79 ms 88280 KB Output is correct
3 Correct 77 ms 88280 KB Output is correct
4 Incorrect 75 ms 88464 KB Output isn't correct
5 Halted 0 ms 0 KB -