이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// https://oj.uz/problem/view/info1cup20_tabletennis
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using db = double;
using str = string;
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;
using vi = vector<int>;
using vb = vector<bool>;
using vl = vector<ll>;
using vd = vector<db>;
using vs = vector<str>;
using vpi = vector<pi>;
using vpl = vector<pl>;
using vpd = vector<pd>;
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(0);
#define FASTIOF ios_base::sync_with_stdio(false); fin.tie(0);
#define mp make_pair
#define f first
#define s second
#define sz(x) (int)(x).size()
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define sor(x) sort(all(x))
#define rev(x) reverse(all(x))
#define rsz resize
#define ins insert
#define ft front()
#define bk back()
#define pb push_back
#define pf push_front
#define lb lower_bound
#define ub upper_bound
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define F0R(i, a) FOR(i, 0, a)
#define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--)
#define R0F(i, a) ROF(i, 0, a)
#define EACH(a, x) for (auto& a : x)
ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); }
ll fdiv(ll a, ll b) { return a / b - ((a ^ b) < 0 && a % b); }
template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }
template<class T> void remDup(vector<T>& v) { sor(v); v.erase(unique(all(v)), v.end()); }
const int MOD = 1e9 + 7;
const int MX = 15e4 + 410;
const ll INF = 1e18;
int N, K, A[MX]; unordered_map<int, int> freq; vi possSum;
bool valid(int sum) {
int L = 1, R = N + K;
int numGroup = 0;
while (L < R) {
while (A[L] + A[R] != sum) {
if (A[L] + A[R] < sum) {
L++;
}
else {
R--;
}
if (L >= R) {
break;
}
}
if (L >= R) {
break;
}
numGroup++;
if (numGroup >= N / 2) {
return true;
}
L++;
R--;
}
return false;
}
int main() {
FASTIO;
cin >> N >> K;
FOR(i, 1, N + K + 1) {
cin >> A[i];
}
FOR(i, 1, K + 2) {
FOR(j, N, N + K + 1) {
freq[A[i] + A[j]]++;
}
}
EACH(P, freq) {
if (P.s > K / 2) {
possSum.pb(P.f);
}
}
int res = 0;
EACH(sum, possSum) {
if (valid(sum)) {
res = sum;
break;
}
}
vi ans(N);
int L = 1, R = N + K;
int numGroup = 0;
while (L < R) {
while (A[L] + A[R] != res) {
if (A[L] + A[R] < res) {
L++;
}
else {
R--;
}
}
ans[numGroup] = A[L];
ans[N - 1 - numGroup] = A[R];
numGroup++;
if (numGroup >= N / 2) {
break;
}
L++;
R--;
}
EACH(i, ans) {
cout << i << " ";
}
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |