이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<typename K> using hset = gp_hash_table<K, null_type>;
template<typename K, typename V> using hmap = gp_hash_table<K, V>;
using namespace std;
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define eb emplace_back
#define smax(x, y) (x = max(x, y))
#define smin(x, y) (x = min(x, y))
#define FOR(i, a, b) for (int i = (a); i < (b); ++i)
#define F0R(i, a) FOR(i,0,a)
#define ROF(i, a, b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i, a) ROF(i,0,a)
using ll = long long;
using ld = long double;
template<typename T>
using vv = vector<vector<T>>;
using vi = vector<int>;
using ii = array<int, 2>;
using vii = vector<ii>;
using vvi = vv<int>;
using vll = vector<ll>;
using l2 = array<ll, 2>;
using vl2 = vector<l2>;
using vvll = vv<ll>;
template<typename T>
using minq = priority_queue<T, vector<T>, greater<T>>;
template<typename T>
using maxq = priority_queue<T>;
const ll M = 1000000007;
const ll infll = M * M;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int k, n;
cin >> k >> n;
ll res{};
vii pe;
F0R(i, n) {
char p, q;
int s, t;
cin >> p >> s >> q >> t;
if (p == q) res += abs(t - s);
else pe.pb({s, t});
}
if (k == 1) {
if (pe.empty()) {
cout << res << '\n';
return 0;
}
res += pe.size(); // distance from people crossing the bridge
vll v;
for (auto [s, t] : pe) {
v.pb(s);
v.pb(t);
}
sort(all(v));
ll x = (v[v.size() / 2 - 1] + v[v.size() / 2]) / 2;
for (auto [s, t] : pe) {
res += abs(s - x) + abs(t - x);
}
cout << res << '\n';
}
}
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