Submission #492605

#TimeUsernameProblemLanguageResultExecution timeMemory
492605Biaz과수원 (NOI14_orchard)C++17
8 / 25
1090 ms972 KiB
#include <bits/stdc++.h> #define int long long //#define double long double #define Nanase_Kurumi_aka_menhera_chan_is_mine ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); #define pb push_back #define pi pair<int, int> #define ALL(i) i.begin(),i.end() #define gcd(i,j) __gcd(i,j) #define fi first #define se second #define eps 0.00000001 #define ist insert #define DNE nullptr //#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector,fast-math") //#pragma GCC optimize("O2") int max(int x,int y){return x>=y?x:y;} int min(int x,int y){return x>=y?y:x;} using namespace std; typedef int ll; const int N=100005; const int M=1000005; const int MOD=1000000007;//998244353; const int INF=1000000000000000000;//2147483647; int n,m,tot; int a[N]; inline void sol(){ cin >>n>>m; for (int i=0;i<n;i++) for (int j=1;j<=m;j++) cin >>a[j],a[j]+=a[j-1]; tot=a[m]; int ans=min(a[m],m-tot); for (int i=1;i<=m;i++) a[i]=2*a[i]-i; for (int i=0;i<=m;i++) for (int j=i;j<=m;j++) ans=min(ans,tot-a[j]+a[i]); assert(ans>=0); cout <<ans<<'\n'; } signed main(){ Nanase_Kurumi_aka_menhera_chan_is_mine int _=1; //cin >>_; while (_--) sol(); return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...