이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/*#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("avx,avx2,fma")*/
#include <bits/stdc++.h>
#define for1(i,a,b) for (int i = a; i <= b; i++)
#define for2(i,a,b) for (int i = a; i >= b; i--)
#define int long long
#define sz(a) (int)a.size()
#define pii pair<int,int>
#define pb push_back
/*
__builtin_popcountll(x) : Number of 1-bit
__builtin_ctzll(x) : Number of trailing 0
*/
const long double PI = 3.1415926535897932384626433832795;
const int INF = 1000000000000000000;
const int MOD = 1000000007;
const int MOD2 = 1000000009;
const long double EPS = 1e-6;
using namespace std;
int n, m, q;
int a[200005], d[200005], up[200005][18];
pii res;
set<int> id[200005], se[200005];
vector<int> g[200005];
void dfs(int u, int p) {
for1(i,1,17) up[u][i] = up[up[u][i - 1]][i - 1];
for (auto v : g[u]) if (v != p) {
d[v] = d[u] + 1;
up[v][0] = u;
dfs(v, u);
}
}
int lca(int u, int v) {
if (d[u] < d[v]) swap(u, v);
for1(i,0,17) if ((d[u] - d[v]) & (1 << i)) u = up[u][i];
if (u == v) return u;
for2(i,17,0) if (up[u][i] != up[v][i]) {
u = up[u][i];
v = up[v][i];
}
return up[u][0];
}
signed main() {
ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
// freopen("cf.inp", "r", stdin);
// freopen("cf.out", "w", stdout);
cin >> n >> m >> q;
for1(i,1,n - 1) {
int a, b;
cin >> a >> b;
g[a].push_back(b);
g[b].push_back(a);
}
dfs(1, 0);
for1(i,1,m) {
cin >> a[i];
id[a[i]].insert(i);
}
for1(i,1,m - 1) se[lca(a[i], a[i + 1])].insert(i);
while (q--) {
int op;
cin >> op;
if (op == 1) {
int i, u;
cin >> i >> u;
id[a[i]].erase(i);
if (i > 1) se[lca(a[i - 1], a[i])].erase(i - 1);
if (i < n) se[lca(a[i], a[i + 1])].erase(i);
a[i] = u;
id[a[i]].insert(i);
if (i > 1) se[lca(a[i - 1], a[i])].insert(i - 1);
if (i < n) se[lca(a[i], a[i + 1])].insert(i);
}
else {
int l, r, u;
cin >> l >> r >> u;
auto it = id[u].lower_bound(l);
if (it != id[u].end() && *it <= r) {
cout << *it << " " << *it << "\n";
continue;
}
auto it2 = se[u].lower_bound(l);
if (it2 != se[u].end() && *it2 < r) {
cout << *it2 << " " << *it2 + 1 << "\n";
continue;
}
cout << "-1 -1\n";
}
}
}
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