제출 #490135

#제출 시각아이디문제언어결과실행 시간메모리
490135rainliofficialRobot (JOI21_ho_t4)C++17
100 / 100
860 ms84296 KiB
#include <bits/stdc++.h> typedef long long ll; using namespace std; const ll INF = 1e18; struct Edge { int to, c; ll p; }; map<int, vector<Edge>> graph[100001]; ll dp[100001]; map<int, ll> dp2[100001], psum[100001]; int main() { cin.tie(0)->sync_with_stdio(0); int n, m; cin >> n >> m; for (int i = 1; i <= m; i++) { int u, v, c; ll p; cin >> u >> v >> c >> p; graph[u][c].push_back({v, c, p}); graph[v][c].push_back({u, c, p}); psum[u][c] += p; psum[v][c] += p; } memset(dp, 0x3f, sizeof dp); dp[1] = 0; priority_queue<tuple<ll, int, int>> pq; pq.push({0, 1, 0}); while (pq.size()) { ll cost; int node, c; tie(cost, node, c) = pq.top(); pq.pop(); if (c) { if (dp2[node][c] != -cost) continue; for (Edge i : graph[node][c]) { // We can't flip i in this case ll case1 = psum[node][c] - i.p; if (case1 - cost < dp[i.to]) { dp[i.to] = case1 - cost; pq.push({-dp[i.to], i.to, 0}); } } } else { if (dp[node] != -cost) continue; for (auto& i : graph[node]) { for (Edge j : i.second) { // Case 1: We don't flip j ll case1 = psum[node][j.c] - j.p - cost; if (case1 < dp[j.to]) { dp[j.to] = case1; pq.push({-dp[j.to], j.to, 0}); } // Case 2: We flip j but not another edge of the same colour ll case2 = j.p - cost; if (case2 < dp[j.to]) { dp[j.to] = case2; pq.push({-dp[j.to], j.to, 0}); } // Case 3: We flip j and another edge of the same colour ll case3 = -cost; if (!dp2[j.to].count(j.c) || case3 < dp2[j.to][j.c]) { dp2[j.to][j.c] = case3; pq.push({-dp2[j.to][j.c], j.to, j.c}); } } } } } cout << (dp[n] > INF ? -1 : dp[n]); return 0; }
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